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3 years ago

List 3 examples in which friction helps us or makes things easier in our daily life. Explain the effect of friction for each.

Physics

2 answers:

Kisachek [45]3 years ago

8 0

<span>Friction can help us play tennis, knock down bowling pins, and cook dinner.</span>

Free_Kalibri [48]3 years ago

5 0

The three examples in which friction helps us or makes things easier in our daily life are :

(a) Friction helps us to walk. if there were no friction, we wouldn't be able to push earth backwards by our feet . Thus we will not get the reaction force from earth which is necessary for walking.

(b) Conveyor belts will not work if there is no friction. Friction provides a grip for the conveyor belts to transfer motion from one part of a machine to another.

(c) Cars, buses and all locomotives will not be able to stop once they are set in motion if the friction was absent. friction provides a braking forces for these vehicles to stop.

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maks197457 [2]

Answer:

Specific heat capacity is an intensive property and does not depend on sample size.

Explanation:

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3 years ago

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2 years ago

using hooke's law, f spring = k triangle x, find the elastic constant of a spring that stretches 2 cm when a 4 newton force is a

Ksivusya [100]

As we know that spring force is given as

$F = kx$

here we know that

F = 4 N

x = 2 cm = 0.02 m

now from the above equation we will have

$4 = k(0.02)$

$k = 200 N/m$

so the elastic constant of the spring will be 200 N/m

8 0

3 years ago

This is science :)

iris [78.8K]

1 to 5 would be your answer

8 0

3 years ago

A 50-cm-long spring is suspended from the ceiling. A 230g mass is connected to the end and held at rest with the spring unstretc

alukav5142 [94]

Answer:

k = 25.07 N/m

Amplitude = 9 cm

f = 1.66 Hz

Explanation:

Given:

- The original length of the spring L_o = 50 cm

- The mass hanged m = 230 g

- The amount of stretch given 2x = 18 cm @lowest point.

Find:

a. What is the spring constant? (K=)

b. What is the amplitude of the oscillation?

c. What is the frequency of the oscillation?

Solution:

- Make a FBD of the hanging mass, There are two external forces acting on it that is the force of gravity due to its weight and the springs restoring force when its stretched to its lowest point. After hanging the mass on the spring a new equilibrium position is achieved which also causes the spring to stretch. We can apply the Equilibrium conditions at this point in vertical direction as:

k*x - m*g = 0

k = m*g / x

Where, x is the extension of the spring or mean stretch. which 0.5*amplitude (Lowest point). x = 9 cm

k = 0.23*9.81 / 0.09

k = 25.07 N/m

Answer: For part a we have the stiffness of the spring k = 25.07 N/m

- The amplitude of the oscillating motion is the half the amount of total stretch or the amount the spring extends above or below the mean position.

Amplitude = x = 9 cm

- The frequency of any oscillatory motion which can be modeled by SHM can be expressed as:

f = 1 / 2*p* sqrt ( k / m )

- Plug the values in:

f = 1 / 2*pi* sqrt (25.07 / 0.23 )

f = 1.66 Hz

Answer: For part c the frequency of oscillation is f = 1.66 Hz

8 0

3 years ago