Answer:
<h3>The answer is 20 N</h3>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
<h3>Force = mass × acceleration</h3>
From the question
mass = 10 kg
acceleration = 2 m/s²
We have
Force = 10 × 2
We have the final answer as
<h3>20 N</h3>
Hope this helps you
Answer: when the dipole moment and electric field are parallel
Explanation: The formulae that relates the potential energy of a dipole, dipole moment and strength of electric field is given as
u = p * E cosθ
Where, u= dipole potential energy, p = dipole moment, E = strength of electric field.
The expression is at maximum when θ = 0 (cos 0° = 1)
Hence the function for potential energy will be greatest when θ = 0° which implies that the dipole moment and strength of electric field are parallel to each other.
Answer:
<h3>The answer is 0.67 m/s²</h3>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
f is the force
m is the mass
From the question we have
We have the final answer as
<h3>0.67 m/s²</h3>
Hope this helps you
Answer:
g_x = 3.0 m / s^2
Explanation:
Given:
- Change in length of spring [email protected] = 22.6 cm
- Time taken for 11 oscillations t = 19.0 s
Find:
- The value of gravitational free fall g_x at plant X:
Solution:
- We will assume a simple harmonic motion of the mass for which Time is:
T = 2*pi*sqrt(k / m ) ...... 1
- Sum of forces in vertical direction @equilibrium is zero:
F_net = k*x - m*g_x = 0
(k / m) = (g_x / x) .... 2
- substitute Eq 2 into Eq 1:
2*pi / T = sqrt ( g_x / x )
g_x = (2*pi / T )^2 * x
- Evaluate g_x:
g_x = (2*pi / (19 / 11) )^2 * 0.226
g_x = 3.0 m / s^2
Answer:
25N
Explanation:
Assuming the lab is on earth:
w = mg = 2.5 (9.81) = 25N