The diagrams show vectors. Which diagram represents the vector addition C = A

A 16.5-kg crate starts at rest at the top of a 60.0° incline. The coefficients of friction are μs = 0.400 and μk = 0.300. The cr

irga5000 [103]

Answer:

t = 1.62 s

Explanation:

given,

mass of the block m₁ = 16.5 Kg

m₂ = 8 Kg

angle of inclination = 60°

μs = 0.400 and μk = 0.300

time to slide 2 m = ?

a) let a is the acceleration of the block m₁ downward.

Net force acting on m₂,

F₂ = T - m₂ g

m₂a = T - m₂ g

$a = \dfrac{T}{m_2} - g$ .......(1)

net force acting on m₁

F₁ = m₁g sin(60°) - μ_k m₁g cos (60°) - T

m₁ a = m₁g sin(60°) - μ_k m₁g cos (60°) - T

$a = g sin(60^0) - \mu_k g cos (60^0) - \dfrac{T}{m_1}$ .........(2)

from equations 1 and 2

$\dfrac{T}{m_2} - g = g sin(60^0) - \mu_k g cos (60^0) - \dfrac{T}{m_1}$

$\dfrac{T}{m_2} +\dfrac{T}{m_1} = g+ g sin(60^0) - \mu_k g cos (60^0)$

$T\dfrac{m_1+m_2}{m_2\times m_1} = g+ g sin(60^0) - \mu_k g cos (60^0)$

$T = \dfrac{g+ g sin(60^0) - \mu_k g cos (60^0)}{\dfrac{m_1+m_2}{m_2\times m_1}}$

$T = {m_2\times m_1}\dfrac{g+ g sin(60^0) - \mu_k g cos (60^0)}{{m_1+m_2}}$

$T = {16.5\times 8}\dfrac{9.8 + 9.8 sin(60^0) - 0.3\times 9.8 cos (60^0)}{{16.5+8}}$

T = 90.61 N

from equation (1)

$a = \dfrac{90.61}{8} - 9.8$ .......(1)

a = 1.52 m/s²

let t is the time taken

Apply,

d = ut + 0.5 a t²

2 = 0 + 0.5 x 1.52 x t²

$t = \sqrt{2.63}$

t = 1.62 s

5 0

3 years ago

Sunlight is observed to focus at a point 18. 5 cm behind a lens. what kind of lens is it? b. what is the focal length of the len

topjm [15]

Sunlight focuses at a point 18.5 cm behind the lens. As daylight comes from an indefinite distance, so it is a real image. The lenses that will focus on the parallel rays behind the lens are converging lenses.

What is a converging lens?

A converging lens causes parallel rays of light to come to a focal point.
A convex lens is a converging lens.
A converging lens has a positive focal length.
A converging lens forms a real or virtual image of a real object.

For more information, please visit: brainly.com/question/3359672?referrer=searchResults

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5 0

2 years ago

In a regression analysis, if sse = 200 and ssr = 300, then the coefficient of determination is:_________

Nataliya [291]

0.600

In a regression analysis, if sse = 200 and ssr = 300, then the coefficient of determination is: <u>0.600</u>

<u></u>

1. You have that the data set having SSR=300 and SSE=200

2. Therefore you have the coefficient of determination is:

r²=SSR/SSTO

SSTO=SSR+SSE

3. Then, when you substitute the values, you obtain:

SSTO=200+300

SSTO=500

r²=300/500

4. So, you have that the result is:

r²=0.6

As a result, as you can see, the solution to the previous exercise is that the coefficient of determination is 0.6

<h3>What exactly is the connection between SST, SSR, and SSE?</h3>

The difference between SST and SSR is the amount of Y's variability that is still unaccounted for after using the regression model, also known as the sum of squared errors (SSE). Sum of squares of residual can be used to directly calculate SSE.

To learn more about regression analysis visit:

brainly.com/question/12213669

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8 0

2 years ago

g (a) Calculate the speed of a proton that is accelerated from rest through a potential difference of 127 V. km/s (b) Calculate

Kisachek [45]

Answer:

Explanation:

3 0

3 years ago

Gas to liquid pls fast answer

wariber [46]

Answer:

wet farts, JK its condensation.

4 0

3 years ago