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2 years ago

Which of these is an example of formation of a substance with a different identity

Chemistry

2 answers:

Anna71 [15]2 years ago

8 0

Uhmm, a hard one High School.. . I will have to go with B:sieving flour and spices.

Anit [1.1K]2 years ago

7 0

Answer:

Mixing sand in water.

Explanation:

MIxing of sand in water is an example of formation of a substance with a different identity. The sand sinks to the bottom in this mixture that's why it is a heterogenous mixture. A heterogenous mixture is a mixture that is not uniform in composition and it includes different substances like solid and liquid mixture.

While other options are may be homogenous mixture and diluted solution which have same composition and may also have same phase like liquid to liquid and powder to powder.

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Wrong answers only! What color is an orange?

Anastaziya [24]

Answer:

Blue

Explanation:

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Calcula la densidad de un cuerpo que tiene la masa de 12g y un volumen de 3cm^3 dar el resultado en unidades del SI

kvv77 [185]

The density is 4 g/cm³ or 4000 kg/m³.

Density = mass/volume = 12 g/3 cm³ = 4 g/cm³

The measurement of 4 g/cm³ is already in SI units.

In SI base units,

Density = (4 g/1 cm³) × (1 kg/1000 g) × (100 cm/1 m)³ = 4000 kg/m³

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3 years ago

A desert would have what type of climate?

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The typically bald, rocky, or sandy surfaces in desert climates hold little moisture and evaporate the little rainfall they receive.

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3 years ago

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Milk of magnesia is often taken to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 te

Igoryamba

Answer:

8.61 mL of the HCl solution

Explanation:

The reaction that takes place is:

2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O

From the given mass of Mg(OH)₂, we can calculate the moles of HCl that are neutralized:

4x10² mg = 400 mg = 0.400g

0.400g Mg(OH)₂ ÷ 58.32g/1mol = 6.859*10⁻³ mol Mg(OH)₂

6.859*10⁻³ mol Mg(OH)₂ * $\frac{1molHCl}{1molMg(OH)_{2}} =$ 3.429x10⁻³ mol HCl

Finally, to calculate the volume of an HCl solution, we need both the moles and the concentration. We can calculate the concentration using the pH value:

pH = -log[H⁺]

1.4 = -log[H⁺]

$10^{-1.4}$ = [H⁺]

0.0398 M = [H⁺] = [HCl] *Because HCl is a strong acid*

Thus, the volume is:

0.0398 M = 3.429x10⁻³mol HCl / Volume

Volume = 8.616x10⁻³ L = 8.62 mL

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3 years ago

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When blood is donated, sodium oxalate solution is used to precipitate Ca2+, which triggers clotting. A 122.0−mL sample of blood

icang [17]

Answer:

[Ca2+] = 3.36 * 10^-8 M

Explanation:

Step 1: Data given

A 122.0−mL sample of blood contains 9.70 * 10^−5 g Ca2+/mL.

A technologist treats the sample with 100.0 mL of 0.1550 M Na2C2O4.

Ksp = 2.30 * 10^−9

Step 2: Calculate mass of Ca2+

Mass Ca2+ = 9.70 * 10^−5 g Ca2+/mL * 122 mL

Mass Ca2+ = 0.011834 grams

Step 3: Calculate moles of Ca2+

Moles Ca2+ = mass Ca2+ / molar mass Ca2+

Moles Ca2+ = 0.011834 grams / 40.078 g/mol

Moles Ca2+ = 2.95 *10^-4 moles = 0.000295

Step 4: Calculate moles of C2O4^2-

Moles C2O4^2- = Molarity * volume

Moles C2O4^2- = 0.1550 M * 0.100 L

Moles C2O4^2- = 0.0155 moles

Step 5: Calculate limiting reactant

Ca2+ is the limiting reactant. It will completely be consumed ( 0.000295 moles).

C2O4^2- is in excess. There will 0.000295 moles be consumed. There will remain 0.0155 - 0.000295 = 0.015205 moles of C2O4^2-

Step 6: Calculate total volume

Total volume = 122.0 mL + 100.0 mL = 222.0 mL = 0.222 L

Step 7: Calculate concentration CaC2O4

[CaC2O4] = 0.000295 mol / 0.222 L

[CaC2O4] = 0.00133 M

Step 8: Calculate concentration of C2O4^2-

[C2O4^2-] = 0.015205 mol / 0.222L

[C2O4^2-] = 0.0685 M

Step 9: Calculate [Ca2+]

Ksp = 2.3 * 10^-9 = [Ca2+] [C2O42-]

2.3 * 10^-9 = X * (X+0.0685)

X = [Ca2+] = 3.36 * 10^-8 M

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3 years ago