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IgorC [24]
3 years ago
14

Select the fastest way to differentiate between the organic and aqueous layers of an extraction.a. Hold a white piece of paper b

ehind the separatory funnel. The organic layer will have a slight yellow color, while the aqueous layer will be colorless.b. Add a few drops of one of the layers to a test tube containing 1 mL of water. Shake the test tube to determine the solubility of the layer in water.c. Separate the layers and heat them. The organic layer will have the lowest boiling point.d. Weigh equal volumes of each layer. The aqueous layer will have the highest mass.
Chemistry
1 answer:
valentinak56 [21]3 years ago
6 0

Answer:

b. Add a few drops of one of the layers to a test tube containing 1 mL of water. Shake the test tube to determine the solubility of the layer in water

Explanation:

Option a is not true, it depends on the compound being extracted.

Option c is not true, although most of the solvents used in extractions have lower boiling point than water there are exceptions, for example toluene.

Option  d is not true. Again most of the solvents used in extractions are less dense than water, there are many exceptions, for example chloroform, so for equal volumes the chloroform layer will weigh more.

Option b. is the correct one.

One will test the  miscibility of the layer in water. If it inmiscible then one would know is the organic layer. If it is the aqueous layer then it will completely be miscible.

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Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha
Citrus2011 [14]

<u>Answer:</u> The mass of lead iodide produced is 9.22 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles

The chemical equation for the reaction of NaI and lead chlorate follows:

Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = \frac{1}{2}\times 0.04=0.02mol of lead iodide

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g

Hence, the mass of lead iodide produced is 9.22 grams

6 0
3 years ago
Predict how many H1 NMR signals (individual resonances, not counting splitting) are expected for the compound.
Lyrx [107]

Answer:

3 H1 NMR signals

Explanation:

NB: kindly check the diagram of the chemical compound in the attached picture.

This particular Question is based on the part of chemistry which is known as spectroscopy. Spectroscopy is used in the Determination or in identifying chemical compounds. H'NMR works on the principle of nuclear magnetic resonance.

In order to solve this question, one has to count the number of hydrogen in unique location. The diagram in the attached show how hydrogen is been counted.

The numbers of signals is the number of different chemical environments in which hydrogen atoms are located.

NB: signals is also the same as peak in H'NMR.

Hence, the number of H1 NMR signals in this chemical compound is 3.

3 0
3 years ago
2C2H2 + 5O2 → 4CO2 + 2 H2O How many grams of CO2 are required to react with exactly 3.00 mol of O2? 106 g 132 g 165 g 76.8 g
cricket20 [7]

Hey there!:

Given the reaction:

2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

5 moles O2 ------------- 4 moles CO2

3.00 moles O2 ----------  ( moles of CO2 ?? )

moles of CO2 = 3.00 * 4 / 5

moles of CO2 =  12 / 5

moles of CO2 = 2.4 moles

So, molar  mass CO2 = 44.01 g/mol

Therefore:

1 mole CO2 -------------- 44.01 g

2.4 moles CO2 ---------- ( mass of CO2 )

mass of CO2 = 2.4 * 44.01 / 1

mass of CO2 = 106 g

Answer A


Hope that helps!

8 0
3 years ago
Consider the chemical equation below.
Aleks [24]
I would say A but then again im not too sure so hope that makes it easier to somehow
6 0
3 years ago
Read 2 more answers
Convert 11.03 moles of calcium nitrate to grams
hichkok12 [17]
Im pretty sure the answer is <span> 0.01218859659g

not 100% sure tho so please consult someone else b4 answering 
i hope this helps!!</span>
6 0
3 years ago
Read 2 more answers
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