The mass of water, H₂O produced from the reaction is 72.06 g
We'll begin by calculating the mass of NH₄NO₃ that reacted and the mass of H₂O produced from the balanced equation.
NH₄NO₃ —> N₂O + 2H₂O
Molar mass of NH₄NO₃ = 80.03 g/mol
Mass of NH₄NO₃ from the balanced equation = 1 × 80.03 = 80.03 g
Molar mass of H₂O = 18.01 g/mol
Mass of H₂O from the balanced equation = 2 × 18.01 = 36.02 g
From the balanced equation above,
80.03 g of NH₄NO₃ reacted to produce 36.02 g of H₂O
Finally, we shall determine the mass of H₂O produced by the reaction of 160.1 g of NH₄NO₃.
From the balanced equation above,
80.03 g of NH₄NO₃ reacted to produce 36.02 g of H₂O.
Therefore,
160.1 g of NH₄NO₃ will react to produce = (160.1 × 36.02) / 80.03 = 72.06 g of H₂O.
Thus, the mass of water, H₂O produced from the reaction is 72.06 g
Learn more on stiochoimetry: brainly.com/question/15048051
