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Savatey [412]
2 years ago
6

The spring has a stiffness k=200 N/m and is unstretched when the 25 kg block is at A. Determine the acceleration of the block wh

en s=0.4 m. The contact surface between the block and the plane is smooth (no friction).
(solve using F=ma for acceleration and U=Δ T+Δ V for velocity)

Engineering
1 answer:
marysya [2.9K]2 years ago
4 0

<u>Acceleration of the block = 3.2 m/s</u>

<u>Explanation:</u>

Given data:

k = 200 N/m

m = 25 kg

s  = 0.4 m

Now, in order to calculate the force that is applied to a spring, we use the formula:

F = ks

where k is the spring constant and s is the extension.

We also know that,

F = ma

where m is the mass and a is the acceleration.

Since both are the formulas for force, we can write as:

ma = ks

   a = ks/m

Now substituting the values in the above equation,

   a = <u>200 × 0.4</u>

            25

   a   = 3.2 m/s

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A tensile test is performed on a metal specimen, and it is found that a true
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600 mpa

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What colour is best for radiative heat transfer? a. Black b. Brown c. Blue d. White
GarryVolchara [31]

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The correct answer is option 'a': Black

Explanation:

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8 0
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Why is it important to know the accuracy and precision of a measuring device? Do you think that the dial caliper manufacturer’s
Leto [7]

Answer:

Accuracy and precision allow us to know how much we can rely on a measuring device readings. ±.001 as a "accuracy" claim is vague because there is no unit next to the figure and the claim fits better to the definition of precision.

Explanation:

Accuracy and Precision: the golden couple.

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±.001 what unit?

The manufacturer says that is an accuracy indicator, nevertheless there is now unit stated so this is not useful to see how accurate the device is. Additionally, That notation is more used to refer to device tolerances, that is to say the range of possible values the instrument may show when reading and element. It means it tells us more about the device precision during measurments than actual accuracy. I would recommend the following to the dial calipers manufacturers to better explain its measurement specifications:

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3 0
3 years ago
A 75 ! coaxial transmission line has a length of 2.0 cm and is terminated with a load impedance of 37.5 j75 !. If the relative p
Cerrena [4.2K]

Answer:

4.26

Explanation:

The wavelength λ is given by:

\lambda=v/f=c/nf\\c=speed\ of\ light=3*10^8m/s,f=frequency=3*10^9Hz,n=permittivity=2.56\\\\\lambda=3*10^8/(2.56*3*10^9)=0.0625\ m\\

Phase constant (β) = 2π/λ

βl = 2π/λ × l

l = 2 cm = 0.02 m

βl = 2π/0.0625 × 0.02=2.01 rad = 115.3°

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Z_L=load\ impedance=37.5+j75\\\\Z_o=characteristic impedance = 75\ ohm\\\\\tilde {Z_L}=Z_L/Z_o=37.5+j75/75=0.5+j

\tilde {Z_{in}}=\frac{\tilde {Z_{L}}+jtan\beta l}{1+j\tilde {Z_{L}}tan\beta l}=\frac{0.5+j+jtan(115.2)}{1+j(0.5+j)tan(115.2)}=0.253-j0.274\\  \\Z_{in}=Z_o\tilde {Z_{in}}=75(0.253-j0.274)=19-j20.5\\\\\Gamma_L=\frac{Z_L-Z_0}{Z_L+Z_o}=\frac{37.5+j75-75}{37.5+j75+75}=0.62\angle 83^o\\\\\Gamma_{in}=\frac{Z_{in}-Z_0}{Z_{in}+Z_o}=\frac{19-j20.5-75}{19-j20.5+75}=0.62\angle -147^o\\\\VSWR=\frac{1+\rho}{1-\rho} =\frac{1+0.62}{1-0.62}=4.26

6 0
3 years ago
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