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Sauron [17]
3 years ago
7

A compound has the molecular formula C3H8. Which class of organic compounds does it belong to?

Chemistry
1 answer:
Serhud [2]3 years ago
7 0

Answer & Explanation:

  • The compound is considered as hydrocarbon because it contains only carbon and hydrogen.
  • Also, it is alkane compound because all the bonds are saturated (single bonds).
  • CH₃CH₂CH₃ "propane".
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Which units are used to measure both velocity and speed? Select three options
Ede4ka [16]

Answer and Explanation:

The options aren't listed in your question, but here are some units that are regularly and normally used (in the classroom and in the outside world):

(The SI unit of distance and displacement is the meter. The SI unit of time is the second.)

<u>Meters per Second (m/s)</u>

kilometers per hour (km/hr)

kilometers per second (km/sec)

To find the average speed, you do distance divided by time.

To find the average velocity, you do the final position minus the initial position, divided by the final time minus the initial time.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

<em><u></u></em>

<em><u>I hope this helps!</u></em>

8 0
3 years ago
What is the bond angle in a tetrahedral molecule?
levacccp [35]
109.5

tetrahedral shape:
number of electron pair = 4,
number of bonded pair = 4,
number of lone pair = 0.
7 0
3 years ago
Read 2 more answers
Calculate the density for a rectangular block using the following measurements: Length = 10 cm, Width = 1.1 cm, Height = 15 cm,
Ksivusya [100]

Answer:

0.40 g/cm3

Explanation:

density = mass / volume.

mass = 65.2 grams

volume = 10*1.1*15=165 cm3

so density = 65.2/165=0.40 g/cm3

3 0
3 years ago
Hydrogen gas was collected by water displacement. what was pressure of the h2 collected if the temperature was 26°c?
Vedmedyk [2.9K]
The ideal gas law may be written as
p= \frac{\rho R T}{M}
where
p = pressure
ρ =density
T = temperature
M = molar mass
R = 8.314 J/(mol-K)

For the given problem,
ρ = 0.09 g/L = 0.09 kg/m³
T = 26°C = 26+273 K = 299 K
M = 1.008 g/mol = 1.008 x 10⁻³ kg/mol

Therefore
p= \frac{(0.09 \, kg/m^{3})*(8.314 \, J/(mol-K))*(299 \, K)}{1.008 \times 10^{-3} \, kg/mol} =2.2195 \times 10^{5} \, Pa

Note that 1 atm = 101325 Pa
Therefore
p = 2.2195 x 10⁵ Pa
   = 221.95 kPa 
   = (2.295 x 10⁵)/101325 atm
   = 2.19 atm

Answer:
2.2195 x 10⁵ Pa (or 221.95 kPa or 2.19 atm)

4 0
3 years ago
Elements that have the following qualities: Lustrous, Solid at Room Temperatures, They react and form Basic Compounds, Great con
Tatiana [17]

Answer:

They are classified as METALS.

Explanation:

Elements are simple substances that cannot be chemically broken down into smaller substances. Based on different characteristics, they are classified into 3 namely:

- metals

- non metals and

- metalloid( mainly act as semi- conductor).

METALS are the type of elements that loses electrons to form positive ion, that is, they are electropositive elements. They are distinguished by the following characteristics:

- LUSTROUS: they have the ability to reflect light from its surface.

- At room temperature: Metals are solid are room temperature with the exception of Mercury which is liquid at room temperature.

- They react and form Basic Compounds

- Great conductor: most metals are great conductors of heat and electricity because they possess free electrons.

- Melting Point: they have high melting points.

8 0
3 years ago
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