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Colt1911 [192]
3 years ago
7

For water, the value for the latent heat of vaporization is 6.8 times greater than the latent heat of fusion. Imagine we were ad

ding heat at a constant rate to a block of ice in a beaker on a hot plate, and it took 4 minutes for the ice to melt completely. How long would it take, after the water started boiling, for the beaker to be completely empty (the liquid water totally converted to water vapor)?
Chemistry
1 answer:
Tom [10]3 years ago
8 0

Answer:

Time of vaporization = 0.588 minutes

Explanation:

The latent heat of fusion is the heat required to change the substance from solid (ice) to liquid completely, without further increase in temperature.

The latent heat of vaporization is the heat required to change a liquid to gas completely, without an increase in temperature.

Latent heat of vaporization = 6.8 times Latent heat of fusion

This means that the time it takes for the latent heat of vaporization to complete vaporization is 6.8 times lesser than the time it takes for the latent heat of fusion to complete fusion

Time of vaporization = 6.8 times lesser than time of fusion

Time of vaporization = (time of fusion) ÷ 6.8

where: Time of fusion = 4 minutes

∴ Time of vaporization = 4 ÷ 6.8

Time of vaporization = 0.588 minutes

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<u>Answer:</u> The empirical formula for the given compound is C_3H_6O

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In 18g of water, 2 g of hydrogen is contained.

So, in 0.00258 g of water, \frac{2}{18}\times 0.00258=0.000286g of hydrogen will be contained.

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Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.00172g}{12g/mole}=1.43\times 10^{-4}moles

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