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scoray [572]
3 years ago
9

Hii pls helpnme to write out the ionic equation ​

Chemistry
1 answer:
Oxana [17]3 years ago
3 0

Answer:

CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)

Explanation:

According to this question, sodium carbonate reacts with sulfuric acid to form aqueous sodium sulfate, carbon dioxide and water. The balanced chemical equation is as follows:

Na2CO3(aq) + H2SO4(aq) → Na2SO4(aq) + CO2(g) + H2O(l)

- Next, split compounds that are aqueous into ions.

2Na+(aq) + CO32-(aq) + 2H+(aq) + SO42-(aq) → 2Na+(aq) + SO42-(aq) + CO2(g) + H2O(l)

- Next, we cancel out the spectator ions, which are ions that remain the same in the reactants and products side of a chemical reaction. The spectator ions in this equation are 2Na+(aq) and SO42-(aq).

CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)

- Hence, the balanced ionic equation is as follows:

CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)

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Humans exhale carbon dioxide when they breathe. If the concentration of carbon dioxide in the air that
Verizon [17]

Answer:

4 people

Explanation:

In order to know this, we need to gather the data.

First we have 3.5x10⁴ g of LiOH. This grams are to be last for the whole 9 days mission shuttle.

So, we first need to know how much of CO₂ will be neutralized by this mass. This can be done calculating the moles of LiOH, and then, the moles of CO₂

The molecular weight of LiOH is 23.94 g/mol and for CO₂ is 44 g/mol so:

CO₂ + 2LiOH -------> Li₂CO₃ + H₂O

moles of LiOH = 3.5x10⁴ / 23.94 = 1461.988 moles

We have a mole ratio of 1:2 so the moles of CO₂:

moles CO₂ = 1461.988 / 2 = 730.994 moles

The mass of CO₂ for the 9 days will be:

m CO₂ = 730.994 * 44 = 32163.74 g

Now, let's see how much it has to be used per day:

m CO₂/d = 32163.74 / 9 = 3573.75 g per day

This means that we can only take a few astronauts, and this number is:

n° astronaut = 3573.75 / 8.8x10²

<h2>n° astronaut = 4.06</h2><h2>In other words, only 4 astronaut</h2>
3 0
3 years ago
Match the description to the type of mixture.
Softa [21]

Answer:

1-homo

2-hetero

3-hetero

4-homo

Explanation:

7 0
2 years ago
Calculate the extinction coefficient where the concentration is in mg/ml and the path length is 1 cm. What dilutions of the stoc
Airida [17]

Complete Question

The complete question is show on the first uploaded image

Answer:

This is shown on the second,third , fourth and fifth image

Explanation:

This is shown on the second,third , fourth and fifth image

4 0
3 years ago
Na2CO3 + 2HCl ---------&gt; 2NaCl + CO2 + H2O How many moles of NaCl are produced from the reaction of 1.67 x 1022 molecules of
dexar [7]

Answer:

0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.

Explanation:

The balanced reaction is:

Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • HCl: 2 moles
  • NaCl: 2 moles
  • CO₂: 1 mole
  • H₂O: 1 mole

On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

amount of moles=\frac{1.67*10^{22}molecules*1mole }{6.023*10^{23}molecules}

amount of moles= 0.0277 moles

In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

amount of moles of NaCl=\frac{0.0277 moles of Na_{2} CO_{3}*2 moles of NaCl }{1 mole of Na_{2} CO_{3}}

amount of moles of NaCl= 0.0554 moles

<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>

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3 years ago
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