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Artyom0805 [142]
3 years ago
15

Three blocks of metal at the same temperature are placed on a hot stove. Their specific heat capacities are listed below.Rank th

em from greatest to least in how quickly each warms up.Steel, 450 J/(kg⋅∘C)Aluminum, 910 J/(kg⋅∘C)Copper, 390 J/(kg⋅∘C)?
Chemistry
1 answer:
JulijaS [17]3 years ago
7 0

Answer:

Copper>Steel>Aluminium

Explanation:

Hello,

Since the heat capacity accounts for the required heat to increase by 1°C, 1 kg of the metal, copper is the one that has the lower heat capacity, it means that it requires the least amount of energy to warm up (increase its temperature), this could be substantiated via the mathematical definition of heat capacity:

H=mC(T_2-T_1)

Solving for T_2:

T_2=T_1+\frac{H}{mC}

It means that the lower the heat capacity, the higher the final temperature.

Best regards.

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An atom of which element has the greatest attraction for electrons in a chemical bond?
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Answer is (4) - Se.

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3 years ago
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A plot of binding energy per nucleon Eb A versus the mass number (A) shows that nuclei with a small mass number have a small bin
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Answer:

6He =   4.90 MeV/Nucleon

8Li =     5.18  MeV / Nucleon

62Ni =   8.82 MeV / Nucleon

115 In =  8.54 MeV / Nucleon

Explanation:

Our strategy here is to remember that when the mass of a given nuclei is calculated from the sum of the mass of its  protons and neutrons, this mass is greater than  the actual  value . This is the mass defect.

Now this mass defect we can convert to energy  by utilizing Einstein´s equation, E = mc².This is  the binding energy.

For 6He with actual mass 6.0189 u ( He has Z = 2, that is 2 protons )

mass protons =   2 x 1.0078 u  =  2.0516 u

mass neutrons = 4 x 1.0087 u  =  4.0348 u

predicted mass = (2.0516 + 4.0348) u = 6.0504 u

mass defect = (6.0504 - 6.0189) u = 0.0315 u

Now we need to convert this mass expressed in atomic mass units to kilograms ( 1 u = 1.66054 x 10⁻²⁷ Kg )

0.0315 u x 1.66054 x 10⁻²⁷ Kg =5.231 x 10⁻²⁹ Kg

E =5.231x 10⁻²⁸ Kg x (3 x 10⁸ m/s )² = 4.707 x 10⁻¹²J

Finally we will convert this energy in Joules to eV

E = 4.707 x 10⁻¹²  J x 6.242 x 10¹⁸ eV/J = 2.94 x 10⁷ eV = 29.4 MeV

E per nucleon for 6He = 29.4 MeV / 6 =4.90 MeV / Nucleon

Now the calculations for the rest of the nuclei are performed in similar manner with the following results:

8Li = 5.18 MeV / Nucleon

62Ni = 8.82 MeV / Nucleon

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