Answer:

The initial volume of the chlorine gas

Explanation:

Given:

P1= 686mmHg

P2= 991mmHg

V2= 5076mL

V1=?

According to Boyle's law which states that at a constant temperature, the pressure on a gas increases as it's volume decreases.

It can be expressed as : P1V1 = P2V2

Where P1 is the initial pressure

P2= final pressure

V1= initial volume

V2 = final volume

V1= (991mmHg*507.6mL)/686mmHg

V1=503031.6/686

Therefore, The initial volume of the chlorine gas

We need to know the relationship between atmospheric pressure and the density of gas particles in an area of increasing pressure.

The relationship is: **As air pressure in an area increases, the density of the gas particles in that area increases.**

For any gaseous substance, density of gas is directly proportional to pressure of gas.

This can be explained from idial gas edquation:

PV=nRT

PV=RT [where, w= mass of substance, M=molar mass of substance]

PM=RT

PM=dRT [where, d=density of thesubstance]

So, for a particular gaseous substance (whose molar mass is known), at particular temperature, pressure is directly related to density of gaseous substance.

Therefore, as air pressure in an area increases, the density of the gas particles in that area increases.

Answer: 40cm^3

Explanation:

Since the The air today is approximately one-fifth oxygen, the approximate volume of oxygen in 200cm3 of air would be:

= 1/5 × 200

= 40cm

The answer is 40cm^3

H20 is water?????booom

Yes answer

<span>3) which is an example of a physical change

</span><span>a) grinding pepper</span>