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dybincka [34]
3 years ago
11

A three-step mechanism has been suggested for the formation of carbonyl chloride: Step 1: Cl2 → 2 Cl Step 2: Cl + CO → COCl Step

3: COCl + Cl2 → COCl2 + Cl Which species is an intermediate in the mechanism?
Chemistry
1 answer:
ladessa [460]3 years ago
8 0

Answer:

COCl species is an intermediate in the mechanism.

Explanation:

Intermediates are those chemical species which only appears for a short time in a course of a chemical reaction. They act as product and reactant during the reaction. Also they do not appear in overall chemical reaction.

Step 1: Cl_2\rightarrow 2 Cl

Step 2: Cl + CO\rightarrow COCl

Step 3: COCl + Cl_2\rightarrow COCl_2 + Cl

Overall reaction :

2Cl_2+CO\rightarrow COCl_2+2Cl

As we can see that all the chemicals are present in the overall reaction beside COCl.

COCl species is an intermediate in the mechanism.

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\displaystyle \text{Electrostatic Potential Energy} = -\frac{k\cdot (q_1\cdot q_2)}{r},

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Krypton and bromine are right next to each other in the same period. Their atomic radii will be similar to each other. The separation r between the outermost electron and the nucleus will also be similar for the two elements.

The first charge q_1 can be the electron. However, data show that for elements after helium, the second charge q_2 is smaller than the sum of charges on all protons in the nucleus. It turns out that the inner shell electrons (all of which are also negative) repel electrons in the outermost valence shell. The effective nuclear charge Z_\text{eff} of a neutral atom is <em>approximately</em> the same as the number of protons minus the number of non-valence electrons. That number will be slightly larger for krypton than for bromine. As a result, the electrostatic potential energy on a 4p (the outermost orbital for both Kr and Br) electron of krypton will be more negative than that on a 4p electron in bromine. Removing that electron will take more energy in Kr than in Br. The first ionization energy of Kr is hence greater than that of Br.

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