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weeeeeb [17]
4 years ago
13

A solution of sulfuric acid has a concentration of 0.0980 g/L. If the density of the acid is 1.84 g/mL, what is the concentratio

n in ppm?
Chemistry
2 answers:
mariarad [96]4 years ago
6 0
The answer is 98ppm.

The ppm (Parts per million) is also a concentration unit. 1 ppm is equivalent to 1mg/L
Now, concentration of the solution of sulfuric acid is 0.0980 g/L.
We rewrite, 0.0980 g = 0.0980*1000 mg = 98mg
Therefore, the concentration of the sulfuric acid solution is 98 mg/L = 98 ppm.
umka2103 [35]4 years ago
6 0

Answer:

The concentration of H2SO4 = 53.3 ppm

Explanation:

Given:

Concentration of H2SO4 = 0.0980 g/L= 98.0mg/L

Density of H2SO4 = 1.84 g/ml = 1.84 kg/L

Formula:

ppm = parts per million

1 ppm = 1\frac{mg(solute)}{kg(solution)}

ppm( H2SO4 )=\frac{98.0 mg/L}{1.84 kg/L} =53.3 mg/kg

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3 years ago
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Consider the neutralization reaction 2 HNO 3 ( aq ) + Ba ( OH ) 2 ( aq ) ⟶ 2 H 2 O ( l ) + Ba ( NO 3 ) 2 ( aq ) A 0.120 L sample
k0ka [10]

Answer:

The concentration of the HNO3 solution is 0.150 M

Explanation:

<u>Step 1:</u> Data given

Volume of the unknown HNO3 sample = 0.120 L

Volume of the 0.200 M Ba(OH)2 = 45.1 mL

<u>Step 2:</u> The balanced equation

2HNO3 + Ba(OH)2 ⟶ Ba(NO3)2 + 2H2O

<u>Step 3:</u> Calculate moles Ba(OH)2

moles Ba(OH)2 = molarity * volume

moles Ba(OH)2 = 0.200 M * 0.0451 L

moles Ba(OH)2 = 0.00902 moles

<u>Step 4:</u> Calculate moles of HNO3

For 1 mole of Ba(OH)2 we need 2 moles of HNO3

For 0.00902 moles of Ba(OH)2 we need 2*0.00902 = 0.01804 moles

<u>Step 5</u>: Calculate molarity of HNO3

molarity = moles / volume

molarity = 0.01804 / 0.120 L

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6 0
3 years ago
When an acid solution exactly neutralizes a base
o-na [289]

Answer:a weak acid and a weak base

Explanation:

7 0
3 years ago
Please help me, Thank you!
babymother [125]

Answer:

amount of charge

Explanation:

Oxygen and sulfur are both in Group 16, which means they have a -2 charge. They have two more electrons than protons, making the charge of the ion negative.

Hope that helps.

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I think so

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