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weeeeeb [17]
4 years ago
13

A solution of sulfuric acid has a concentration of 0.0980 g/L. If the density of the acid is 1.84 g/mL, what is the concentratio

n in ppm?
Chemistry
2 answers:
mariarad [96]4 years ago
6 0
The answer is 98ppm.

The ppm (Parts per million) is also a concentration unit. 1 ppm is equivalent to 1mg/L
Now, concentration of the solution of sulfuric acid is 0.0980 g/L.
We rewrite, 0.0980 g = 0.0980*1000 mg = 98mg
Therefore, the concentration of the sulfuric acid solution is 98 mg/L = 98 ppm.
umka2103 [35]4 years ago
6 0

Answer:

The concentration of H2SO4 = 53.3 ppm

Explanation:

Given:

Concentration of H2SO4 = 0.0980 g/L= 98.0mg/L

Density of H2SO4 = 1.84 g/ml = 1.84 kg/L

Formula:

ppm = parts per million

1 ppm = 1\frac{mg(solute)}{kg(solution)}

ppm( H2SO4 )=\frac{98.0 mg/L}{1.84 kg/L} =53.3 mg/kg

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vfiekz [6]
According to Gases law, we know, 
PV/T = Constant

So, P₁V₁/T₁ = P₂V₂/T₂

Here, P₁ = 108 kPa
V₁ = 592.2 mL
T₁ = 10+273 = 283 K
P₂ = ?
V₂ = 750 mL
T₂ = 28.9+273 = 301.9

Substitute their values, 

108 * 592.2 / 283 = P₂ * 750 / 301.9
P₂ = 63957.6 * 301.9 / 283 * 750
P₂ = 19308799.44 / 212250
P₂ = 90.97 kPa

In short, Your Final Answer would be: 90.97 kPa

Hope this helps!
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