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weeeeeb [17]
3 years ago
13

A solution of sulfuric acid has a concentration of 0.0980 g/L. If the density of the acid is 1.84 g/mL, what is the concentratio

n in ppm?
Chemistry
2 answers:
mariarad [96]3 years ago
6 0
The answer is 98ppm.

The ppm (Parts per million) is also a concentration unit. 1 ppm is equivalent to 1mg/L
Now, concentration of the solution of sulfuric acid is 0.0980 g/L.
We rewrite, 0.0980 g = 0.0980*1000 mg = 98mg
Therefore, the concentration of the sulfuric acid solution is 98 mg/L = 98 ppm.
umka2103 [35]3 years ago
6 0

Answer:

The concentration of H2SO4 = 53.3 ppm

Explanation:

Given:

Concentration of H2SO4 = 0.0980 g/L= 98.0mg/L

Density of H2SO4 = 1.84 g/ml = 1.84 kg/L

Formula:

ppm = parts per million

1 ppm = 1\frac{mg(solute)}{kg(solution)}

ppm( H2SO4 )=\frac{98.0 mg/L}{1.84 kg/L} =53.3 mg/kg

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Answer:

Option C

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Explanation:

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Considering the options given in the question above,

For A:

CH₃CH₂OCH₂CH₃ is an ether compound with general formula ROR' where R and R' are both alkyl group.

For B:

CH₃CH₂CH₂CH₂OH is an alcohol with general formula ROH where R is an alkyl group.

For C:

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For D:

CH₃CH₂C=OCH₂CH₃ is a ketone compound with general formula RC=OR' where R and R' are both alkyl group

For E:

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