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weeeeeb [17]
3 years ago
13

A solution of sulfuric acid has a concentration of 0.0980 g/L. If the density of the acid is 1.84 g/mL, what is the concentratio

n in ppm?
Chemistry
2 answers:
mariarad [96]3 years ago
6 0
The answer is 98ppm.

The ppm (Parts per million) is also a concentration unit. 1 ppm is equivalent to 1mg/L
Now, concentration of the solution of sulfuric acid is 0.0980 g/L.
We rewrite, 0.0980 g = 0.0980*1000 mg = 98mg
Therefore, the concentration of the sulfuric acid solution is 98 mg/L = 98 ppm.
umka2103 [35]3 years ago
6 0

Answer:

The concentration of H2SO4 = 53.3 ppm

Explanation:

Given:

Concentration of H2SO4 = 0.0980 g/L= 98.0mg/L

Density of H2SO4 = 1.84 g/ml = 1.84 kg/L

Formula:

ppm = parts per million

1 ppm = 1\frac{mg(solute)}{kg(solution)}

ppm( H2SO4 )=\frac{98.0 mg/L}{1.84 kg/L} =53.3 mg/kg

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That is because Alchemy is not based on real research and facts, but rather on magic and occultism. Sure, many things in it have been used as basics for some chemistry, but most is false and incorrect.
6 0
3 years ago
What is the density of water if you have 50.0 grams of water and a volume of 50.0 millimeters
Gnom [1K]

Answer:

\boxed {\tt 1.0 \ g/mL}

Explanation:

Density can be found by dividing the mass by the volume.

d=\frac{m}{v}

The mass of the water is 50.0 grams.

The volume of the water is 50.0 milliliters.

m= 50.0\ g \\v=50.0 \ mL

Substitute the values into the formula.

d=\frac{50.0 \ g}{50.0 \ mL}

Divide.

d= 1.0  \ g/mL

The density of the water is 1.0 grams per milliliter. Also, remember that the density of pure water is always 1.0 g/mL or g/cm³

8 0
3 years ago
The total volume of seawater is 1.5 x 1021L .Assume that seawater contains 3.1 percent sodium chloride by mass and that its dens
son4ous [18]

Answer:

Mass in kg = 4.7*10^19 kg

Mass in tons = 5.2*10^16 tons

Explanation:

<u>Given:</u>

Total volume of sea water = 1.5*10^21 L

Mass % NaCl in seawater = 3.1%

Density of seawater = 1.03 g/ml

<u>To determine:</u>

Total mass of NaCl in kg and in tons

<u>Calculation:</u>

Unit conversion:

1 L = 1000 ml

The volume of seawater in ml is:

=\frac{1.5*10^{21}L*1000ml }{1L} =1.5*10^{24} ml

Mass\ seawater = Density*volume = 1.03g/ml*1.5*10^{24} ml=1.5*10^{24}g

Mass\ NaCl\ in\ seawater = \frac{3.1}{100}*1.5*10^{24}  g=4.7*10^{22} g

To convert mass from g to Kg:

1000 g = 1 kg

Mass\ seawater(kg) = \frac{4.7*10^{22}g*1kg }{1000g} =4.7*10^{19} kg

To convert mass from g to tons:

1 ton = 9.072*10^6 g

Mass\ seawater(tons) = \frac{4.7*10^{22}g*1ton }{9.072*10^{6}g } =5.2*10^{16} tons

5 0
3 years ago
When the average kinetic energy of a gas is increased, the motion of the gas particles
Monica [59]
The gas particles move faster.
6 0
2 years ago
What is the chemical combination of calcium cloride and aluminum ​
nexus9112 [7]

Answer:

Calcium chloride react with aluminum to produce calcium and aluminum chloride. This reaction takes place at a temperature of 600-700°C.

CaCl2+F2 -> CaF2 + Cl2

7 0
2 years ago
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