1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svet-max [94.6K]
4 years ago
7

Write a balanced half-reaction describing the oxidation of aqueous gold(i) cations to aqueous gold(iii) cations.

Chemistry
1 answer:
bezimeni [28]4 years ago
7 0
<span>Balanced half-reaction: Au</span>⁺<span>(aq) </span>→ <span> Au</span>³⁺(aq) + 2e⁻.
Oxidation reaction is increasing of oxidation number of element, because element or ion lost electrons in chemical reaction.
Gold lost two electrons and change oxidation number from +1 to +3.
Reduction is lowering oxidation number because element gain electrons.
You might be interested in
Given that Ag-107 (51.839% abundance) and the mass ratio: Ag-109/Ag-107=1.0187.
Ymorist [56]

Answer:

Atomic mass of Ag-107 = 106.94 amu

Explanation:

Let the mass of Ag-107 be y

Since the mass ratio of Ag-109/Ag-107 is 1.0187, the mass of Ag-109  is 1.0187 times heavier than the mass of Ag-107

Mass of Ag-109  = 1.0187y

Relative atomic mass of Ag = sum of (mass of each isotope * abundance)

Relative atomic mass of Ag = 107.87

Abundance of Ag-107 = 51.839% = 0.51839

Abundance of Ag-109 = 41.161% = 0.48161

107.87 = (y * 0.51839) + (1.018y * 0.48161)

107.87 = 0.51838y + 0.49027898y

107.87 = 1.00865898y

y = 107.87/1.00865898

y = 106.94 amu

Therefore, atomic mass of Ag-107 = 106.94 amu

5 0
4 years ago
How many electrons does carbon have if it has six protons?
lidiya [134]

it is 6, all isotopes of carbon have 6 electrons and 6 protons which is why its atomic number is 6

4 0
3 years ago
Compare melting point freezing point and boiling point
Tresset [83]
Melting point- the temperature at which a substance has changed from a solid to a liquid
freezing- the temperature at which a substance chanes from liquid to a solid
boiling point- the temperature at which a substance changes from a liquid to a gas phase
4 0
3 years ago
Gasoline has a density of 0.7197 grams per milliliter. Calculate the mass, in grams, of a sample of gasoline with a volume of 48
barxatty [35]

Answer:

34.9103 or 34.9 g

Explanation:

Remember Density is a broken heart: m/v.

In this scenario (Let x = # of grams in the sample of gasoline),

D = 0.7198 g/mL = x g / 48.5 mL

So,

(0.7198 g/mL) * (48.5 mL) = x g

x g = 34.9103 = 34.9 g (Accounting for Significant Figures)

8 0
2 years ago
A small container of perfume is opened in a classroom. Soon every student in the room smells the perfume. Explain this in terms
iogann1982 [59]

When perfume or cologne is sprayed into the air, it turns into a gas and its particles mix with other air particles that quickly move around the room. This is because gas is the least dense of the three states of matter. It moves quickly into any space or volume because it has the least density. This is called diffusion, when molecules or particles move from areas with high concentration to low concentration areas. 

7 0
3 years ago
Other questions:
  • ¿En qué fecha, Mendeléiev creo su tabla periódica según la leyenda?
    14·1 answer
  • The specific heat capacity of aluminum is 0.215 cal/g°
    10·1 answer
  • Which expression represents a reaction rate?
    10·1 answer
  • Which statements describe a good hypothesis? Check all that apply.
    15·2 answers
  • Increased industrialization has caused a rise in harmful acid rain precipitation that affects plant and marine life. A sample of
    10·1 answer
  • 20.0m equals how many feet ? Round your answers to the nearest tenth.
    10·1 answer
  • Which of the following statements is not true, according to the kinetic theory
    6·1 answer
  • Relative abundance definition
    14·2 answers
  • True or false measurement depends on how hard gravity pulls on object?
    12·1 answer
  • How many miligrams are in 75 nanogram?​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!