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svet-max [94.6K]
3 years ago
7

Write a balanced half-reaction describing the oxidation of aqueous gold(i) cations to aqueous gold(iii) cations.

Chemistry
1 answer:
bezimeni [28]3 years ago
7 0
<span>Balanced half-reaction: Au</span>⁺<span>(aq) </span>→ <span> Au</span>³⁺(aq) + 2e⁻.
Oxidation reaction is increasing of oxidation number of element, because element or ion lost electrons in chemical reaction.
Gold lost two electrons and change oxidation number from +1 to +3.
Reduction is lowering oxidation number because element gain electrons.
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Empirical formula of the Cyclopropane = CH_{2}

Molecular formula  of the Cyclopropane = C_{3} H_{6}

Cyclopropane is a cyclic compound having 3 carbon atoms in a ring.

As we know carbon is having 4 valency, that means it can form 4 bonds with other atoms.

In case of cyclopropane each carbon atom is attached with 2 carbon atoms in a ring, so 2 valency of each carbon atom is used in a ring formation.

The remaining 2 valency are satisfied by hydrogen atoms.

Here, 3 carbons are there so 6 hydrogens are used to satisfy their valency.

An empirical formula is a simple representation of ratio of the atoms present, while a molecular formula is a detailed representation of the total number of atom.

So here, carbon and hydrogen ratio is 1:2 , from this the Empirical formula of the Cyclopropane became CH_{2}

And the molecular formula of  the Cyclopropane is C_{3} H_{6}.

Learn more about molecular formula here...

brainly.com/question/15092254

#SPJ10

6 0
2 years ago
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