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alexira [117]
3 years ago
7

A skater increases her speed uniformly from 2.0 meters per second to 7.0 meters per second over a distance of 12 meters. the mag

nitude of her acceleration as she travels this 12 meters is
Physics
1 answer:
AVprozaik [17]3 years ago
6 0
<span>The magnitude of her acceleration as she travels this 12 meters is 1.875m/s^2</span>
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The driver of a car traveling at 30.5 m/s slams on the brakes so that the car undergoes a constant acceleration, skidding to a c
dolphi86 [110]

Answer:

-6.8 m/s²

Explanation:

Given:

v₀ = 30.5 m/s

v = 0 m/s

t = 4.5 s

Find: a

a = (v − v₀) / t

a = (0 m/s − 30.5 m/s) / 4.5 s

a = -6.8 m/s²

4 0
3 years ago
It is claimed that if a lead bullet goes fast enough, it can melt completely when it comes to a halt suddenly, and all its kinet
TEA [102]

Answer:

v=346.05\ m.s^{-1}

Explanation:

Given:

initial temperature of the lead bullet, T_i=43^{\circ}C

latent heat of fusion of lead, L_f=2.32\times 10^4\ J.kg^{-1}

melting point of lead, T_m=327.3^{\circ}C

We have:

specific heat capacity of lead, c=129\ J.kg^{-1}.K^{-1}

<em>According to question the whole kinetic energy gets converted into heat which establishes the relation:</em>

\rm KE=(heat\ of\ rising\ the\ temperature\ from\ 43\ to\ 327.3\ degree\ C)+(heat\ of\ melting)

\frac{1}{2} m.v^2=m.c.\Delta T+m.L_f

\frac{1}{2} m.v^2=m(c.\Delta T+L_f)

\frac{v^2}{2} =129\times(327.3-43)+23200

v=346.05\ m.s^{-1}

3 0
3 years ago
A .5 kg air puck moves to the right at 3 m/s, colliding with a 1.5kg air puck that is moving to the left at 1.5 m/s.
Bas_tet [7]

Answer:

Explanation:

Total momentum of the system before the collision

.5 x 3 - 1.5 x 1.5 = -0.75 kg m/s towards the left

If v be the velocity of the stuck pucks

momentum after the collision = 2 v

Applying conservation of momentum

2 v = -  .75

v =  - .375 m /s

Let after the collision v be the velocity of .5 kg puck

total momentum after the collision

.5 v + 1.5 x .231 = .5v +.3465

Applying conservation of momentum law

.5 v +.3465 = - .75

v = - 2.193 m/s

2 ) To verify whether the collision is elastic or not , we verify whether the kinetic energy is conserved or not.

Kinetic energy before the collision

= 2.25 + 1.6875

=3.9375 J

kinetic energy after the collision

= .04 + 1.2 =1.24 J

So kinetic energy is not conserved . Hence collision is not elastic.

3 ) Change in the momentum of .5 kg

1.5 - (-1.0965 )

= 2.5965

Average force applied = change in momentum / time

= 2.5965 / 25 x 10⁻³

= 103.86 N

5 0
3 years ago
A young man heaves a 6.5 kg rock at a velocity of 6.9 m/s. What is the kinetic energy of the rock?
earnstyle [38]

Answer:

Hope it will help you a lot.

7 0
2 years ago
an object of mass m is rotating about a fixed axis with angular momentum l. its moment of inertia about this axis is i. what is
Tems11 [23]

The Kinetic energy would be 1/2IL².

<h3>What is Rotational Kinetic energy ?</h3>

  • Rotational energy also known as angular kinetic energy is defined as: The kinetic energy due to the rotation of an object and is part of its total kinetic energy. Rotational kinetic energy is directly proportional to the rotational inertia and the square of the magnitude of the angular velocity.

As we know linear Kinetic energy = 1/2mv²

 where m= mass and v= velocity.

Similarly rotational kinetic energy is given by = 1/2IL²

 where I- moment of inertia and L=angular momentum.

To know more about the Kinetic energy , visit:

brainly.com/question/29807121

#SPJ4

8 0
1 year ago
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