Answer:

Explanation:
is the angle between the velocity and the magnetic field. So, the magnetic force on the proton is:

A charged particle describes a semicircle in a uniform magnetic field. Therefore, applying Newton's second law to uniform circular motion:

is the centripetal force and is defined as:

Here
is the proton's speed and
is the radius of the circular motion. Replacing this in (1) and solving for r:

Recall that 1 J is equal to
, so:

We can calculate
from the kinetic energy of the proton:

Finally, we calculate the radius of the proton path:

Work or energy spent=force times distance=25N*4m=100Nm
power=energy or work divided by time=100Nm/5s=20Nm/s
To solve this problem it is necessary to apply the concepts related to the Force from Hook's law as well as the definition of the period provided by the same definition.
We know that the Force can be defined as

Where
k = Spring constant
x = Displacement
g = Gravity
m = mass
At the same time the period of a spring mass system is defined as

Where
m = Mass
k = Spring constant
Our values are given as,
m = 0.404kg
x = 0.666m
Replacing to find the value of the Spring constant we have that



Now using the formula of the period we know that



Finally, if the oscillation was 0.359m
The maximum height will be determined by the total length of that oscillation being equivalent to



Answer:
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Explanation: