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MAXImum [283]
4 years ago
5

A vertical spring 0.100 meter long is elongated to a length of -.119 meter when a 1.00 kilogram mass is attached to the bottom o

f the spring. the spring constant of this spring is
Physics
1 answer:
Nookie1986 [14]4 years ago
4 0
By definition we have that the force of the spring is given by:
 F = -k * deltax
 Where,
 k: spring constant
 deltax = elongation
 Let's clear k:
 k = -F / delta x
 k = mg / delta x
 delta x = 0.119 -0.1 = 0.019m
 Substituting the values:
 k = (1) * (9.81) / (. 019)
 k = 516 N / m
 Answer:
<span> the spring constant of this spring is
</span> k = 516 N / m
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300\times 0.2(T_f-23)+236\times 1(T_f-87)

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296T_f=20532+1380=21912

T_f=\frac{21912}{296}=74^{\circ} C

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