Question

A vertical spring 0.100 meter long is elongated to a length of -.119 meter when a 1.00 kilogram mass is attached to the bottom of the spring. the spring constant of this spring is

Answer 1

By definition we have that the force of the spring is given by:
 F = -k * deltax
 Where,
 k: spring constant
 deltax = elongation
 Let's clear k:
 k = -F / delta x
 k = mg / delta x
 delta x = 0.119 -0.1 = 0.019m
 Substituting the values:
 k = (1) * (9.81) / (. 019)
 k = 516 N / m
 Answer:
 the spring constant of this spring is
 k = 516 N / m