Why do you think there is not a periodic table of compounds? Explain with evidence.

1 answer:

4 0

Compounds are composed of different elements in a fixed proportions. For example, 1 atom of oxygen (O) combines with 2 atoms of hydrogen (H) to form one molecule of water (H2O) compound. Similarly other numbers of atoms would produce other chemical compounds. Even adding 1 more atom of oxygen would convert the water (H2O) into hydrogen peroxide(H2O2). Even if we were only to list the ones we know there are over 20 million known compounds.

In order to list all possible compounds such a table would rapidly become combinatoric nightmare of such size that it would not be practical to use even with a computer database and it would consist of over 100 billion possible compounds containing only H, C, O and N.

Creating a table to handle all possible elements would mean a table of many trillions of compounds.

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how many electrons does chlorine need to gain to become an ion? will it become positively charged cation or negatively charged a

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Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine. CCl4(g) + (1/2)O

madam [21]

The question is incomplete, here is the complete question:

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine.

$CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c=4.4\times 10^9$ at 1,000 K

Calculate Kc for the reaction $2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)$

Answer: The value of $K_c'$ for the final reaction is $1.936\times 10^{19}$

Explanation:

The given chemical equations follows:

$CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c$

We need to calculate the equilibrium constant for the equation, which is:

$2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)$

As, the final reaction is the twice of the initial equation. So, the equilibrium constant for the final reaction will be the square of the initial equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c'=(K_c)^2$