Question

Find the x intercepts of thr following parabola y= -4x^2 + 8x +12

Answer 1

For this case we must find the x-intersepts values of the following equation:

 $y = -4x ^ 2 + 8x + 12$

Doing y = 0 we have:

$0 = -4x ^ 2 + 8x + 12$

Dividing between -4 on both sides of the equation:

$x ^ 2-2x-3 = 0$

We factor, we look for two numbers that when multiplied by -3 and when added by -2. These are -3 and 1:

$-3 + 1 = -2\\-3 * 1 = -3\\(x-3) (x + 1) = 0$

Thus, the x-intercepts values are:

$x_ {1} = 3\\x_ {2} = - 1$

Answer:

$x_ {1} = 3\\x_ {2} = - 1$

Answer 2

Answer:

x=-1 or x=3

Step-by-step explanation:

This is a quadratic equation

You can use the graph tool to visualize the x-intercepts on the graph as attached below.

x=-1 or x=3