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Snowcat [4.5K]
3 years ago
6

Which of the following best defines molar heat capacity? Group of answer choices The quantity of heat required to raise the temp

erature of 1 gram of a substance by 1°C The quantity of heat required to lower the temperature of 1 liter of a substance by 1°C The quantity of heat required to raise the temperature of 1 mole of a substance by 1K The quantity of heat required to raise the temperature of 1 gram of a substance by 1°F
Chemistry
1 answer:
motikmotik3 years ago
8 0

Answer: The quantity of heat required to raise the temperature of 1 mole of a substance by 1K

Explanation:

As the temperature change is same in all scales of temperature.

The quantity of heat required to raise the temperature of a substance by one degree Celsius or one degree Kelvin or one degree Fahrenheit is called the heat capacity.

The quantity of heat required to raise the temperature of 1 gram of substance by one degree Celsius one degree Kelvin or one degree Fahrenheit is called as specific heat capacity.

The quantity of heat required to raise the temperature of 1 mole of substance by one degree Celsius or one degree Kelvin or one degree Fahrenheit is called as molar heat capacity.

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Cassidee walks 1-mile north and then turns and walks 2 miles west. Distance Displacement
Gemiola [76]

Answer:

3 miles?

Explanation:

if you walk one mile North and then turn and walk another two miles you walk 3 miles and then turn around and walk back in the same direction you would end backup at the one-mile Mark he began. So three miles there two miles back

4 0
2 years ago
Determine the moles of H+ reacting with the metal based on the following experimental data. 10.00 mL of 1.00 M HCl solution is a
musickatia [10]

Answer:

Approximately 1.876 \times 10^{-3}\; \rm mol.

Explanation:

Convert both volumes to standard units (that is: liters.)

  • 10.00 \; \rm mL = 10.00 \times 10^{-3}\; \rm L = 1.000 \times 10^{-2}\; \rm L.
  • 27.08 \; \rm mL = 27.08 \times 10^{-3}\; \rm L = 2.708 \times 10^{-2}\; \rm L.

Number of moles of \rm HCl initially present (in the 10.00\; \rm mL solution at 1.00\; \rm M.)

n(\mathrm{HCl}, \, \text{initial}) = \displaystyle c \cdot V = 1.00\times 1.000 \times 10^{-2}= 1.000\times 10^{-2}\; \rm mol.

Number of moles of \rm NaOH from the titration:

n(\mathrm{NaOH}) = c \cdot V = 0.30 \times 2.708 \times 10^{-2} = 8.124 \times 10^{-3}\; \rm mol.

\rm NaOH neutralizes \rm HCl at a 1:1 ratio:

\rm HCl + NaOH \to NaCl + H_2O.

Hence, n(\mathrm{HCl},\, \text{leftover}) = n(\mathrm{NaOH}) = 8.124 \times 10^{-3}\; \rm mol.

\begin{aligned}&n(\mathrm{HCl},\, \text{consumed}) \\ =& n(\mathrm{HCl},\, \text{initial}) - n(\mathrm{HCl},\, \text{leftover}) \\ =& 1.000\times 10^{-2} - 8.124\times 10^{-3} \\ =& 1.876 \times 10^{-3}\; \rm mol\end{aligned}.

3 0
2 years ago
Prior to hosting an international soccer match, the local soccer club needs to replace the artifical turf on their field with gr
GuDViN [60]

Answer:

It will cost $68,620.5 to the club to add the grass turf to their field.

Explanation:

length of the field = l = 0.102 km = 0.102 × 1000 m

( 1km = 1000 m)

Width of the field w = 0.069 km = 0.069 × 1000 m

Area of the field , A= l × w

A=0.102\times 1000 m\times 0.069\times 1000 m=7,038 m^2

Cost of grass turfing = 9.75 \$/m^2

Cost of grass turfing on field of 7,038 m^2 :

=7,038 m^2\times 9.75 \$/m^2=\$68,620.5

It will cost $68,620.5 to the club to add the grass turf to their field.

4 0
3 years ago
Sevin, the commercial name for an insecticide used to protect crops such as cotton, vegetables, and fruit, is made from carbamic
xeze [42]

Answer:

Explanation:

Ratio of mass of C , N , H and O

= .8007 :0.9333:0.2016:2.133

Ratio of moles of C , N , H and O

= .8007/12 : .9333 / 14 : 0.2016 / 1 : 2.133/16

= .0667 : .0667: .2016 : .1333

= .0667 / .0667 : .0667 / .0667 : .2016 /.0667 : .1333 / .0667

= 1 : 1 : 3: 2

Hence empirical formula = CNH₃O₂

7 .

Weight of titanium Ti = 1.916 g

Weight of oxygen = 3.196 - 1.916 = 1.28 g

Ratio of weight of Ti and O

= 1.916 : 1.28

Ratio of moles  of Ti and O

1.916/48 : 1.28/16  [ Molecular  weight of Titanium is 48 ]

= .04 : .08

= .04/.04 : .08/.04

= 1 :2 .

Empirical formula

TiO₂

5 0
2 years ago
Sulfur trioxide is a gas that reacts with liquid water to produce aqueous sulfuric Acid or acid rain what is the equation for th
bearhunter [10]

Answer:

SO₃(g) + H₂O(l) → H₂SO₄(aq)

Explanation:

The<em> molecular formula for the involved species</em> are:

  • Sulfur trioxide = SO₃. ("trioxide" indicates the presence of 3 oxygen atoms).
  • Water = H₂O
  • Sulfuric acid = H₂SO₄

With the above information in mind we can proceed to write the reaction equation:

  • SO₃(g) + H₂O(l) → H₂SO₄(aq)
5 0
2 years ago
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