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Snowcat [4.5K]
3 years ago
6

Which of the following best defines molar heat capacity? Group of answer choices The quantity of heat required to raise the temp

erature of 1 gram of a substance by 1°C The quantity of heat required to lower the temperature of 1 liter of a substance by 1°C The quantity of heat required to raise the temperature of 1 mole of a substance by 1K The quantity of heat required to raise the temperature of 1 gram of a substance by 1°F
Chemistry
1 answer:
motikmotik3 years ago
8 0

Answer: The quantity of heat required to raise the temperature of 1 mole of a substance by 1K

Explanation:

As the temperature change is same in all scales of temperature.

The quantity of heat required to raise the temperature of a substance by one degree Celsius or one degree Kelvin or one degree Fahrenheit is called the heat capacity.

The quantity of heat required to raise the temperature of 1 gram of substance by one degree Celsius one degree Kelvin or one degree Fahrenheit is called as specific heat capacity.

The quantity of heat required to raise the temperature of 1 mole of substance by one degree Celsius or one degree Kelvin or one degree Fahrenheit is called as molar heat capacity.

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El cocodrilo se arrastró durante 20.833 segundos.

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El enunciado presenta omisiones y errores conceptuales. La forma correcta es la siguiente: <em>"Un cocodrilo se arrastró 25 metros hacia la derecha con una  rapidez promedio de 1.2 metros por segundo. ¿Cuántos segundos se arrastró el cocodrilo?"</em>

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t = \frac{25\,m}{1.2\,\frac{m}{s} }

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<em />

8 0
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58. A cylinder of a gas mixture used for calibration of blood gas analyzers in medical laboratories contains 5.0% CO2, 12.0% O2,
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<em><u>Answer and Explanation:</u></em>

Greetings!

Let's~answer~your~question!

Partial ~pressure ~of ~gas ~can ~be ~directly~ calculated ~by ~multiplying ~the~ percentage\\ of~ pressure~ of~ gases~ to ~the ~total ~pressure.

\boxed{Pgas~ = ~P~total~ * \% ~P ~of ~gas}

<em><u>For % of N2 gas: </u></em>

<em><u /></em>100\% - (5\% + 12\%) = 83\% ~N2<em><u /></em>

<em><u /></em>

<em><u /></em>PN_2 ~= ~146~ atm~ *~ 0.83 ~ = 121.18 ~atm<em><u /></em>

<em><u /></em>PO_2 ~= ~146~ atm~ *~ 0.12~ = 17.52 ~atm<em><u /></em>

<em><u /></em>~PCO_2~ = ~146~ atm ~* 0.05 = 7.3 ~atm<em><u /></em>

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