Answer:
-11.4 kJ of heat are released
Explanation:
Balanced reaction- ![HCl+NaOH\rightarrow NaCl+H_{2}O](https://tex.z-dn.net/?f=HCl%2BNaOH%5Crightarrow%20NaCl%2BH_%7B2%7DO)
According to balanced equation, 1 mol of HCl is neutralized by 1 mol of NaOH.
So, 200 mL of 1 M HCl will be completely neutralized by 200 mL of 1 M NaOH.
Let's assume both HCl and NaOH solutions have densities equal to density of pure water.
We know, density = (mass)/(volume)
Density of pure water = 1 g/mL
So mass of both solutions =
= 200 g
So, mass of mixture = (200+200) g = 400 g
Hence, Amount of heat released = ![(m_{mixture}\times C_{mixture}\times \Delta T_{mixture})](https://tex.z-dn.net/?f=%28m_%7Bmixture%7D%5Ctimes%20C_%7Bmixture%7D%5Ctimes%20%5CDelta%20T_%7Bmixture%7D%29)
Where, m represents mass, C represents heat capacity and
represents change in temperature
Let's assume that heat capacity of mixture is also equal to heat capacity of water.
Heat capacity of water = 4.186 J/(g.
)
So, amount of heat released =
=
J=11.4 kJ
As acid-base neutralization reactions are exothermic therefore-
Heat released = -11.4 kJ