Answer:
I = 4.75 A
Explanation:
To find the current in the wire you use the following relation:
(1)
E: electric field E(t)=0.0004t2−0.0001t+0.0004
ρ: resistivity of the material = 2.75×10−8 ohm-meters
J: current density
The current density is also given by:
(2)
I: current
A: cross area of the wire = π(d/2)^2
d: diameter of the wire = 0.205 cm = 0.00205 m
You replace the equation (2) into the equation (1), and you solve for the current I:

Next, you replace for all variables:

hence, the current in the wire is 4.75A
This means acceleration a is constant.
Let
a) vo be the initial speed, at t=0
b) v be the final speed after time t
c) d distance travelled in time t
Then we have:
a) v=vo+a×t
b) v²=vo²+2×a×d (Galilei's equation)
c) d=vo×t+a×t²/2
d) average speed vm=(vo+v)/2
Answer:
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Explanation:
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The cross section is the little tiny circle you see when you cut a wire
and look at the flat, cut end.
The cross-sectional area of the wire is the area of that little circle.
It's equal to
Area = (pi) x (1/4) x (Diameter of the wire)²
Answer: 9m
Explanation:
Our given:
Acceleration- 5m/s^2
Time- 3.6 seconds
Use the equation d = 1/2 • a • t^2
d = 1/2 • 5m/s^2 • 3.6 secs
d = 2.5m/s^2 • 3.6 secs
d = 9m
I hope this is correct