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Tasya [4]
3 years ago
12

Describe the similarities between H3O and NH3. Compare/contrast their shapes and polarities within the context of your answer. T

hese molecules are called isoelectronic. Why
Chemistry
1 answer:
lesantik [10]3 years ago
3 0

Answer:

Explanation:

H_3O^+ also known as hydronium ion is formed as a result of the reaction between an hydrogen proton and a water molecules.

i.e \mathtt{H^+ + H_2O \to H_3O^+}

(molecular geometry for the hydronium ion shows that the lewis structure of hydronium ion possess a three hydrogen ion bonded to a central atom known as oxygen. The oxygen possess a lone pair with a positive ion. So we have three hydrogen atoms and a lone pair attached to the oxygen. We can now say that there are four groups as the steric number in which one of them is a lone pair. This give rise to the trigonal pyramidal shape of the H_3O^+ (hydronium ion) with a bond angle of about 109,5°

Similarly, NH_3 on the other hand also known as ammonia has a shape that can be also determined by the Lewis structure.

IN ammonia,  there are three hydrogen  and a lone pairs of electron spreading out as far away from each other  from the centre nitrogen. In essence, the valence shell electron pair around hydrogens tend to repel each other. Hence, giving it a trigonal pyramidal shape.

From above the similarities between H3O and NH3 is in their molecular geometry in which both  H3O and NH3 have the same shape.

These molecules are called isoelectronic. Why?

Isoelectronic molecules are molecules having the same number of electrons and same electronic configuration  structure. As a result H3O and NH3 possess the same  number of electrons in the same orbitals and they also posses the same structure.

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Given that Avogadro's number is 6.02 X 1023. Calculate the number of molecules present in 100.0moles of
GREYUIT [131]

Answer: 6.02 x 10^25

Explanation:

In order to find the number of molecules you simply multiply the number of moles by 6.022 x 10^23.

1 mole is always equal to 6.022 x 10^23 no matter what element.

100.0 x 6.022 x 10^23 = 6.02 x 10^25

The answer only has three significant figures because 100.0 only has three.

7 0
3 years ago
47. Describe the shapes and relative energies of the s, p, d, and f atomic orbitals.
Fed [463]

Answer:

S orbital:spherical

P orbital:dumbbell

D orbital:double dumbbell

F orbital:complex

Explanation:

4 0
3 years ago
electrons do not follow specific paths, so describing the area where an electron is likely to be is more scientifically accurate
r-ruslan [8.4K]

Answer:

Electrons do not follow specific paths, so the area in which an electron is more scientifically accurate is at the orbitals.

Explanation:

As we know in an atom various electrons are present, they are filled in the orbitals in order to decrease the energy of the atom. These electrons inside the orbitals are arranged from smaller to larger. The lowest one is filled first, the order in which energy is filled is like 1s, 2s, 2p,3s3p,4s,3d etc. The electrons that present far away from the nucleus have the highest energy, the electrons present in the first orbital from the nucleus hold less energy.

3 0
4 years ago
Predict the ground-state electron configuration of the following ions. Write the answer in abbreviated form beginning with noble
Tanzania [10]

Answer: The ground-state electronic configuration of

1) Ru^{2+}=[Kr]4d^6

2) W^{3+]=4f^{14}5d^3

Explanation: The electronic configuration of elements is defined as the distribution of electrons around the nucleus of that element. It depends on the atomic number of the element.

Atomic number of the element = Number of electrons.

  • For Ru-element

Atomic number = 44

Number of electrons = 44

Electronic configuration of Ru-element = [Kr]4d^75s^1

To form Ru^{2+}, 2 electrons are released from the neutral Ru-element.

So, the electronic configuration of Ru^{2+}=[Kr]4d^6

  • For W-element

Atomic number = 74

Number of electrons = 74

Electronic configuration of W-element = [Xe]4f^{14}5d^46s^2

To form W^{3+}, 3 electrons are released from the neutral W-element.

So, the electronic configuration of W^{3+}=[Xe]4f^{14}5d^3

5 0
4 years ago
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WILL GIVE BRAINLIEST - A solution has a [H3O+] of 1 × 10−3 M. What is the [OH−] of the solution?
Hitman42 [59]

Answer:

The answer is 1 x 10 - 11 M.  :))

4 0
3 years ago
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