The reaction is
Zn(s) + 2MnO₂(s) + H₂O(l) ⟶ Zn(OH)₂(s) + Mn₂O₃(s)
The reactants are Zn(s) and MnO₂(s) while Zn(OH)₂(s) and Mn₂O₃(s) products.
Let's see the oxidation state of each compound.
sum of the o.s. of the each element of compound = charge of the compound
O.s of O = -2
O.s of OH⁻ = -1
O.s of Zn(s) = 0
O.s of Mn in MnO₂(s) = x
x + (-2) * 2 = 0
x = +4
O.s of Zn in Zn(OH)₂(s) = a
a + (-1) * 2 = 0
a = +2
O.s of Mn in Mn₂O₃(s) = b
2*b + (-2) * 3 = b
2b = 6
b = +3
Since the O.s is reduced in Mn from +4 to +3, the reduced species is Mn₂O₃(s).
The first orbital to fill with electrons is the 1s orbital. This orbital can hold up to 2 electrons. The 1s orbital is the first orbital.
Hope this helps
Answer:
Single Replacement; 2, 1, 1, 1
Explanation:
2HCl + Zn → H2 + ZnCl2
In a single replacement reaction, one specie is replaced by another specie in a chemical reaction.
If we look at the reaction above, zinc metal reacted with hydrochloric acid. The reaction proceeds in such a manner that zinc replaces hydrogen in hydrochloric acid. This is a single replacement reaction because only one chemical specie is displaced in the reaction.
It should be 3-4 dallors because 8x3 is 24 and that is 3 pounds and you only have one banana left so is supposed to be 3 dallors and change.
