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Gekata [30.6K]
3 years ago
15

7944/0.024 = _______ give the answer to the correct number of significant figures?

Chemistry
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

330,000

Explanation:

Since there are only 2 significant figures in 0.024 ( and 0.024 is the number with the least number of significant numbers), the answer is 330,000, not 331,000.

You might be interested in
Carbon atoms can be identified based on the # of which subatomic particles
34kurt

Answer: protons and neutrons.

The nucleus is made up of 3 subatomic particles that are protons,neutrons and electrons.  

General notation of an element is _{Z}^{A}\textrm{X}

where, X is the Element, A is the Atomic Mass and Z is the Atomic Number

If we know the number of protons we can easily find out the atomic number of any element because Atomic Number = Number of protons in an element.

And in addition if we know the number of neutrons we can easily find out the atomic mass of an element because

Atomic Mass = (Number of protons) + (Number of neutrons)

If we get to know the atomic number and atomic mass, we can easily tell what element is it by looking from the periodic table.

6 0
2 years ago
Consider the following reaction:
iren [92.7K]

Answer:

A. ΔG° = 132.5 kJ

B. ΔG° = 13.69 kJ

C. ΔG° = -58.59 kJ

Explanation:

Let's consider the following reaction.

CaCO₃(s) → CaO(s) + CO₂(g)

We can calculate the standard enthalpy of the reaction (ΔH°) using the following expression.

ΔH° = ∑np . ΔH°f(p) - ∑nr . ΔH°f(r)

where,

n: moles

ΔH°f: standard enthalpy of formation

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g)) - 1 mol × ΔH°f(CaCO₃(s))

ΔH° = 1 mol × (-635.1 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1206.9 kJ/mol)

ΔH° = 178.3 kJ

We can calculate the standard entropy of the reaction (ΔS°) using the following expression.

ΔS° = ∑np . S°p - ∑nr . S°r

where,

S: standard entropy

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g)) - 1 mol × S°(CaCO₃(s))

ΔS° = 1 mol × (39.75 J/K.mol) + 1 mol × (213.74 J/K.mol) - 1 mol × (92.9 J/K.mol)

ΔS° = 160.6 J/K. = 0.1606 kJ/K.

We can calculate the standard Gibbs free energy of the reaction (ΔG°) using the following expression.

ΔG° = ΔH° - T.ΔS°

where,

T: absolute temperature

<h3>A. 285 K</h3>

ΔG° = ΔH° - T.ΔS°

ΔG° = 178.3 kJ - 285K × 0.1606 kJ/K = 132.5 kJ

<h3>B. 1025 K</h3>

ΔG° = ΔH° - T.ΔS°

ΔG° = 178.3 kJ - 1025K × 0.1606 kJ/K = 13.69 kJ

<h3>C. 1475 K</h3>

ΔG° = ΔH° - T.ΔS°

ΔG° = 178.3 kJ - 1475K × 0.1606 kJ/K = -58.59 kJ

5 0
3 years ago
Pure water at 25°C has a pH of<br> (1) 1 (2) 5 • (3) 7<br> (4) 14
Marysya12 [62]

Answer:

7. .........................

8 0
2 years ago
I will mark brainliest!
olganol [36]

Answer:

C ! :)

Explanation:

8 0
3 years ago
Read 2 more answers
. What happens the pH of an acid solution as a base is added?​
Dmitrij [34]

As a base is added to an acidic solution, the H+ ions in solution that make it acidic are slowly neutralized into water (via OH-, the base). As these ions are converted into water the concentration of them decreases, so the pH decreases, as they are directly related.

Hope this helps!

3 0
3 years ago
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