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Rainbow [258]
3 years ago
11

The expression "1in. = 2.54cm" is properly called: A. an equation B. a conversion factor C. a rule of thumb D. an equivalence st

atement
Physics
1 answer:
KIM [24]3 years ago
8 0

Answer:

B. a conversion factor

Explanation:

The expression "1 in. = 2.54 cm" is called a conversion factor.

With this expression inches can be converted to centimeters.

Inversely the expression can also be used to convert centimeters to inches

By rearranging the equation we get

\frac{1}{2.54}\ inches=1\ cm\\\Rightarrow 1\ cm=0.394\ inches

The statement which shows the equal nature of two different expressions is called an equation

Rule of thumb is a general approximation of a result of a test or experiment.

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A roller coaster is travelling 1 m/s at the top of the track. At the bottom of the track, 5 seconds later, it is travelling 36 m
lidiya [134]

Answer:

7m/s²

Explanation:

Given parameters:

Velocity at the top = 1m/s

Velocity at the bottom  = 36m/s

Time  = 5s

Unknown:

Average acceleration = ?

Solution;

Acceleration is the rate of change of velocity with time. It is expressed as;

  A = \frac{v -u}{t}

v is the velocity at the top

u is the velocity at the bottom

t is the time taken

 Now, insert the parameters and solve;

  A = \frac{36 - 1}{5}   = 7m/s²

7 0
3 years ago
What causes wind how does the process reverse itself between day and night?
iris [78.8K]
<span>Wind is nature's way of balancing the temperature between hot and cold. Wind always flows from heat to cool. When night falls, the air cools. And since it gets cooler at night it reverses.</span>
5 0
3 years ago
A ping-pong ball is shot straight north from a popgun at 4.0 m/s. The wind is blowing to the west at 3.0 m/s. What is the actual
Vlad1618 [11]

Actual velocity of the ping-pong ball= 5 m/s

Explanation:

velocity of ping pong ball because of the shot gun= 4 m/s North

velocity added to the ping-pong ball due to the wind=3 m/s

These velocities are perpendicular to each other. so we use Pythagoras theorem to find the resultant velocity of the ping- pong ball

so the actual velocity of the ping-pong ball =V= √4²+3²

V= √25

V= 5 m/s

5 0
4 years ago
An open container holds ice of mass 0.500 kgkg at a temperature of -17.4 âCâC . The mass of the container can be ignored. Heat i
MaRussiya [10]

Answer:

a) t = 235.2minute

b) 260.94minutes

Explanation:

Heat energy is defined as the energy required to change the temperature of a substance by 1kelvin.

It is expressed as H = mc∆t where m is the mass of the water

c is the specific heat capacity of the water/ice

∆t is the change in temperature

Total heat required to melt the ice

H = mLice + mc∆t

Lice is the latent heat of fusion of ice

a) To calculate how much time tmelts passes before the ice starts to melt, we will only calculate heat energy absorb by the ice before it melts.

H = mLice

H = 0.50(334000)

H = 167,000Joules

If heat is supplied to the container at the constant rate of 710 J/minute, the time taken before the ice starts to melt will be:

t = 167,000/710

t = 235.2minutes

b) To calculate how much time trise does it take before the temperature begins to rise above 0°C, we will calculate the total energy absorbed at 0°C first.

H = 0.50(334000) + 0.50(2100)(0-(-17.4)

Note that the ice melts at 0°C which will be the final temperature

H = 167,000+18270

H = 185,270oules

Since heat is supplied to the container at the constant rate of 710 J/minute

710Joules = 1minute

185,270Joules= x

x = 185,270/710

x = 260.94minutes

The time taken before the temperature begins to rise is 260.94minutes:

6 0
3 years ago
Read 2 more answers
What is the work done by a car's braking system when it slows the 1500-kg car from an initial speed of 96 km/h down to 56 km/h i
kondor19780726 [428]

Answer:

-352.275KJ

Explanation:

We are given that

Mass of car=1500kg

Initial speed of car =u=96 km/h=96\times \frac{5}{18}=26.67m/s

1km/h=\frac{5}{18}m/s

Final speed of car=v=56km/h=56\times \frac{5}{18}=15.56m/s

Distance traveled by car=s=55m

We have to find the work done by the car's braking system.

Using third equation of motion

v^2-u^2=2as

(15.56)^2-(26.67)^2=2a(55)

-469.18=110a

a=\frac{-469.18}{110}=-4.27m/s^2

Where negative sign indicates that velocity of car decreases.

Work done by a car's barking system=w=F\times s=ma\times s

Work done by a car's barking system=1500\times -4.27\times 55=352275J

Work done by a car's barking system=-\frac{352275}{1000}=-352.275KJ

1KJ=1000J

Where negative sign indicates that work done in opposite direction of motion.

7 0
4 years ago
Read 2 more answers
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