Answer:
C3H6O3
Explanation:
To find the emperical of the compound,you divide the percentage composition of each element by it's molar mass(C=12, H=1, O=16).
For C,40/12=3.33. For H,6.71/1=6.71
For O,53.19/16=3.33.
Then divide everything by the smallest value which is 3.33
For C,3.33/3.33=1. For H,6.71/3.33=~2.
For O,3.33/3.33=1.
Emperical formula=CH2O
Molecular formula=(CH2O)n=90
(12+2*1+16)n=90
30n=90, n=3
molecular formula=(CH2O)3
molecular formula of lactic acid=C3H6O3.