If it requires 7.0 j of work to stretch a particular spring by 2.1 cm from its equilibrium length, how much more work will be re
1 answer:
You might be interested in
Answer:
The second fish, X2, is moving faster than the first fish, X1
Explanation:
The given parameters for the equation of motion of the fishes are;
X1 = -6.4 m + (-1.2 m/s)×t
X2 = 1.3 m + (-2.7 m/s)×t
The given equation are straight line equations in the slope and intercept form, where the slope is the speed and in m/s and the intercept is the starting point of swimming of the fishes
For the first fish, the intercept = -6.4 m, the slope = the speed = -1.2 m/s
For the second fish, the intercept = 1.3 m, the slope = the speed = -2.7 m/s
Whereby the fishes are swimming in the opposite direction of the measurement of length, we have;
The magnitude of the speed of the second fish , is larger than the magnitude of the speed of the first fish
Therefore, the second fish, X2, is moving faster than the first fish, X1.
Complete Question
Complete Question is attached below
Answer:
Explanation:
From the question we are told that:
Side length s=1.13m
Left field strength
Right field strength
Front field strength
Back field strength
Top field strength
Bottom field strength
Generally, the equation for Charge flux is mathematically given by
Where
Theta for Right,Left,Front and Back are at an angle 90
Therefore
with respect to Right,Left,Front and Back
Generally, the equation for Charge Flux is mathematically also given by
Where
Therefore
Giving
