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Katyanochek1 [597]
3 years ago
5

Identify the decomposition reaction. 2nh3 + h2so4 ⟶ (nh4)2so4 2nabr + ca(oh)2 ⟶ cabr2 + 2naoh 2 no2 ⟶ 2 o2 + n2 3pb + 2h3po4 ⟶ 3

h2 + pb3(po4)2
Chemistry
2 answers:
TEA [102]3 years ago
7 0

A decomposition reaction should look like

A ------> B +C+...

It has to have only one reactant and several products.

2 NO2 ⟶ 2 O2 + N2

Andrei [34K]3 years ago
3 0

Answer : The correct option is, 2NO_2\rightarrow 2O_2+N_2

Explanation :

Decomposition reaction : It is a type of reaction in which a single larger compound decomposes to give two or more smaller molecules as a product.

The general representation of decomposition reaction is :

AB\rightarrow A+B

From the given options,

2NO_2\rightarrow 2O_2+N_2 this reaction a decomposition reaction in which a single nitrogen dioxide decomposes to give oxygen gas and nitrogen gas as a product.

While the other reactions,

2NH_3+H_2SO_4\rightarrow (NH_4)_2SO_4 this reaction is a combination reaction in which the two or more molecules combine to form a larger single molecule as a product.

2NaBr+Ca(OH)_2\righatrrow CaBr_2+2NaOH this is a double displacement reaction in which the cation and the anion of the two reactant exchange their places to give two another compounds as a product.

3Pb+2H_3PO_4\rightarrow 3H_2+Pb_3(PO_4)_2 this is a single displacement reaction in which the more reactive metal displaces the least reaction metal from its compound.

Hence, the decomposition reaction will be, 2NO_2\rightarrow 2O_2+N_2

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A sample of nitrogen occupies a volume of 250 mL at 25 oC. What volume will it occupy at 95 oC?
Volgvan

Answer:

308.7 mL

Explanation:

V1/T1 =V2/T2           T must be in K units

V2 = V1T2/T1

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Which has higher percentage of oxygen: (Fe = 56, O = 16, C = 12) a) FeO b) FeCO3 c) Fe2O3 d) Fe3O4
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3 years ago
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A gas mixture at room temperature contains 10.0 mol CO and 12.5 mol O2. (a) Compute the mole fraction of CO in the mixture. (b)
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Answer:

a. the mole fraction of CO in the mixture of CO and O2.

mole fraction = moles of CO/ Total moles of the mixture

Mole fraction of CO = 10/(10+12.5)=0.444

b. Reaction - CO(g)+½O2(g)→CO2(g)

Stoichiometry: 1 mole of CO react with 0.5mole of O2 to give 1 mole of CO2

So given,

At a certain point in the heating, 3.0 mol CO2 is present. Determine the mole fraction of CO in the new mixture.

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