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laiz [17]
3 years ago
9

Where are metals on the table?

Chemistry
1 answer:
lina2011 [118]3 years ago
5 0
21,22,23,24,25,26,27,28,29,39, on the table
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Sulfur (S) = 32, and of oxygen (O) = 16.
olganol [36]

Answer:

It should be 115.5 amu but you didnt type that as an answer choice so...

Explanation:

Bruh all you had to do was add oxygen and sulfur and subtract from the total to get your answer :D.

5 0
3 years ago
The first law of thermodynamics is a restatement of the
klasskru [66]

the law of thermodyanamic is the restatement of the law of conservation of energy

4 0
3 years ago
Enter the correct 4 digit code (no spaces)
Airida [17]
3618 is the numbers for the graph
3 0
3 years ago
For the reaction 2kclo3(s)→2kcl(s)+3o2(g) calculate how many grams of oxygen form when each quantity of reactant completely reac
barxatty [35]
First, we need to get the molar mass of:

KClO3 = 39.1 + 35.5 + 3*16 = 122.6 g/mol

KCl =39.1 + 35.5 = 74.6 g/mol

O2 = 16*2 = 32 g/mol

From the given equation we can see that:

every 2 moles of KClO3 gives 3 moles of O2

when mass = moles * molar mass

∴ the mass of KClO3 = (2mol of KClO3*122.6g/mol) = 245.2 g

and the mass of O2 then = 3 mol * 32g/mol = 96 g

so, 245.2 g of KClO3 gives 96 g of O2

A) 2.72 g of KClO3: 

when 245.2 KClO3 gives → 96 g  O2

   2.72 g KClO3 gives →  X

X = 2.72 g KClO3 * 96 g O2/245.2 KClO3

    = 1.06 g of O2

B) 0.361 g KClO3:

when 245.2 g KClO3 gives → 96 g O2

     0.361 g KClO3 gives → X

∴ X = 0.361g KClO3 * 96 g / 245.2 g

       = 0.141 g of O2

C) 83.6 Kg KClO3:

when 245.2 g KClO3 gives → 96 g O2

       83.6 Kg KClO3 gives  →  X

∴X = 83.6 Kg* 96 g O2 /245.2 g KClO3

     = 32.7 Kg of O2

D) 22.4 mg of KClO3:

when 245.2 g KClO3 gives → 96 g O2

        22.4 mg KClO3 gives → X

∴X = 22.4 mg * 96 g O2 / 245.2 g KClO3

      = 8.8 mg of O2

     

 


7 0
3 years ago
How is the wavelength of an electromagnetic wave related to the energy of the wave?
Sauron [17]

The equation that relates both energy and wavelength is:

e=\frac{h*c}{lambda}

where e is the energy and lambda is the wavelength.

Therefore, as we can see from this equation, the energy of an electromagnetic wave is inversely related to the wavelength of the electromagnetic wave.

6 0
3 years ago
Read 2 more answers
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