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laiz [17]
3 years ago
9

Where are metals on the table?

Chemistry
1 answer:
lina2011 [118]3 years ago
5 0
21,22,23,24,25,26,27,28,29,39, on the table
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A 12.0 g sample of a metal is heated to 90.0 ◦C. It is then dropped into 25.0 g of water. The temperature of the water rises fro
deff fn [24]

Answer:

The specific heat of the metal is 0.34 J/g°C

Explanation:

Step 1: Data given

Mass of the metal = 12.0 grams

Mass of the water = 25.0 grams

Initial temperature of the metal = 90.0 °C

Initial temperature of the water = 22.5 °C

Final temperature = 25 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of the metal

Qlost = Qgained

Q = m*c*ΔT

Qmetal = -Qwater

m(metal) *c(metal)* ΔT(metal) = -m(water) * c(water) *ΔT(water)

⇒ with mass of metal = 12.0 grams

⇒ with c(metal) = TO BE DETERMINED

⇒ with ΔT(metal) = T2 - T1  = 25.0°C - 90.0 °C = -65.0 °C

⇒ with mass of water = 25.0 grams

⇒ with c(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.0 - 22.5 °C = 2.5 °C

12.0 * c(metal) * -65.0 °C = -25.0g * 4.184 J/g°C * 2.5°C

-780.0 * c(metal) = -2615  ( 2.6*10^3 with sig figs)

c(metal) = 0.335 (=0.34 with sig figs)

The specific heat of the metal is 0.34 J/g°C

3 0
3 years ago
2. Which statement is TRUE about ionic compounds?
oksian1 [2.3K]

Answer:

I think it's c I hope this helps

6 0
2 years ago
What would happen if we did not have an atmosphere?
olganol [36]

Answer:

The air would still be too thin to breathe. The lack of atmosphere would chill the Earth's surface. Organisms that need air to breathe would die.

Explanation:

Hope it helped!

6 0
3 years ago
Concept of mole chemistry question<br><br><br><br>​
vredina [299]

Answer:

How many molecules of water are there in 54 g of H2O H 2 O ? Solution. Molar Mass of H2O H 2 O = 2 + 16 = 18 g/moles. So ,number of moles of H2O H 2 O = Mass/Molar Mass = 54/18 =3 moles. Now 1 moles = 6.022×1023 6.022 × 10 23 molecule.

5 0
2 years ago
Enter your answer in the provided box. phosphorus pentachloride is used in the industrial preparation of organic phosphorus comp
ankoles [38]
I have a helpful trick for such problems. 

Step 1:
Write the equation asked with exact moles given in question,

                                       PCl₃ + Cl₂   →   PCl₅            --------(1)
Step 2:
Write equations given in data along with energies,

                               P₄ + 6Cl₂     →   4PCl₃       Δ<span>H = −1280 kj  -----(2)
</span>
                               P₄ + 10Cl₂   →   4PCl₅       ΔH<span> = −1774 kj  -----(3)

Step 3:
Compare the equation 1 with eq 2 and 3 and modify eq 2 and 3 according to eq 1 both in terms of reactant and product and number of moles. For example in eq 1 PCl</span>₃ is on left hand side and its number of moles is one, so, modify eq, 2 according to eq 1 both in terms of moles and reactant product sides. i.e.
By inter converting eq 2, the sign of energy will change from negative to positive, and divide eq 2 with 4, to have its ratio's equal to eq 1

                             PCl₃   →   1/4 P₄  +  1.5 Cl₂            ΔH  =  +320 KJ

Same steps are done for eq 3, but in this case signs are not changed only moles are changed

                            1/4P₄ + 2.5Cl₂   →   1/4PCl₅            ΔH = −443.5 kj
Now, 
Compare both last equations,

                             PCl₃   →   1/4 P₄  +  1.5 Cl₂            ΔH  =  +320 KJ


                            1/4P₄ + 2.5Cl₂   →   4/4PCl₅            ΔH = −443.5 kj
                        _____________________________________________

                          PCl₃  +  Cl₂     →     PCl₅                   ΔH = -123.5 KJ
7 0
3 years ago
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