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puteri [66]
3 years ago
8

What environmental factors affect sound?

Physics
1 answer:
Mariana [72]3 years ago
7 0

Answer:

Here are 5:

Distance from source to receiver

Wind speed and direction

Wind gradients

Temperature gradients

Atmospheric attenuation

and there are many more...

Hope that was helpful.Thank you!!!

You might be interested in
Water waves and light waves are both examples to
CaHeK987 [17]

Answer:

Transverse waves

Explanation:

Transverse waves are a type of wave that oscillates perpendicular to the direction of movement (the direction of propagation). These type of waves are usually represented by the sine or cosine functions due to the up and down oscillation of the waves.

In the case of water waves the thing that oscillates up and down are the <u>water particles</u> affected by the disturbance.

And for the case light waves what oscillates are the <u>electric and magnetic fields</u>, both oscillating perpendicular to the direction of light propagation.

7 0
3 years ago
A sound signal traveling underwater has a frequency of 230 hertz. The speed of sound underwater is 1.45 × 103 meters/second. Wha
Sholpan [36]

Wavelength  =  (wave speed)  /  (frequency)

                     =      (1,450 m/s)  /  (230 / sec)

                    =              6.30 meters        (rounded)

Hope this helped friend! :)

4 0
3 years ago
Read 2 more answers
To change a tire, you need to use a jack to raise one corner of your car. While doing so, you happen to notice that pushing the
Alja [10]

Answer:

Explanation:

The energy lost by the handle in lowering is equal to the energy gained by the car in raising the height.

As the mass of car is much more as compared to the jack, so the height raised by the car is very small as compared to the handle of jack.

7 0
3 years ago
What Is meant By MA of a machine is 2?​
stich3 [128]

Answer:

See below ~

Explanation:

The Mechanical Advantage (MA) is defined as the ratio between the force produced by the machine to the force applied to it.

=============================================================

So,

⇒ \frac{F(out)}{F(in)} = 2

⇒ This means that the force produced is twice the applied force

7 0
2 years ago
A high school physics instructor catches one of his students chewing gum in class. He decides to discipline the student by askin
kap26 [50]

Answer:

a) \omega \approx 219.911\,\frac{rad}{s}, b) \alpha = 16.916\,\frac{rad}{s^{2}}, c) a_{t} = 1.776\,\frac{m}{s^{2}}, d) a_{n} = 5077.889\,\frac{m}{s^{2}}, e) The direction of the centripetal acceleration experimented by the gum goes to the center of rotation, f) Zero, g) v = 23.091\,\frac{m}{s}.

Explanation:

a) The maximum angular velocity of the fan is:

\omega = (35\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )

\omega \approx 219.911\,\frac{rad}{s}

b) The angular acceleration of the fan is:

\alpha = \frac{\omega-\omega_{o}}{t}

\alpha = \frac{219.911\,\frac{rad}{s}-0\,\frac{rad}{s}}{13\,s}

\alpha = 16.916\,\frac{rad}{s^{2}}

c) The magnitude of the tangential aceleration is:

a_{t} = (16.916\,\frac{rad}{s^{2}} )\cdot (0.105\,m)

a_{t} = 1.776\,\frac{m}{s^{2}}

d) The magnitude of the centripetal acceleration is:

a_{n} = (219.911\,\frac{rad}{s} )^{2}\cdot (0.105\,m)

a_{n} = 5077.889\,\frac{m}{s^{2}}

e) The direction of the centripetal acceleration experimented by the gum goes to the center of rotation.

f) When fan is at full speed, it rotates at constant rate and, hence, there is no angular acceleration. Besides, the tangential acceleration experimented by the gum is zero.

g) The linear speed of the gum is:

v = (219.911\,\frac{rad}{s} )\cdot (0.105\,m)

v = 23.091\,\frac{m}{s}

5 0
3 years ago
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