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puteri [66]
2 years ago
8

What environmental factors affect sound?

Physics
1 answer:
Mariana [72]2 years ago
7 0

Answer:

Here are 5:

Distance from source to receiver

Wind speed and direction

Wind gradients

Temperature gradients

Atmospheric attenuation

and there are many more...

Hope that was helpful.Thank you!!!

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How is the voltage V across the resistor related to the current I and the resistance R of the resistor? (Use I for current and R
VladimirAG [237]

Answer:

This relationship is explained by Ohm's law

Explanation:

Ohm's law states that the current flowing through a circuit or a resistor is directly proportional to the voltage across the resistor and inversely proportional to the resistance. Where current is i, voltage is v and resistance is r, Ohm's law can be represented mathematically as

V= IR

8 0
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Which f the following are true for gravity
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Explanation:

number A

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3 years ago
A 740-kg boulder is raised from a quarry 119 m deep by a long uniform chain having a mass of 550 kg . This chain is of uniform s
Naddika [18.5K]

Answer:

A) the maximum acceleration the boulder can have and still get out of the quarry

B) how long does it take to be lifted out at maximum acceleration if it started from rest

Explanation:

A)

let +y is upward. look below at the free body diagram. the mass M refers to the combined mass of the boulder and chain.

the weight of the chain is:   w_{c} =m_{c} g   and maximum tension is T=2.50 m_{c} g=1.41*10^4N

total mass and weight is :

M =m_{c}+ m_{b} =740kg+550kg=1290 kg

w_{M} =1.2650*10^4N

∑F_{y} =ma_{y}

T-M_{g} =Ma_{y}

a_{y} =(t-M_{g} )/M=(2.50m_{c} -M_{g} )/M=(2.50.550kg-1290kg)(9.8m/s^2)/1290kg

=0.645m/s^2

B)

maximum acceleration

a_{y} =0.645m/s^2\\\\y-y_{0} =119m\\v_{0y} =0

using y-y_{0} =v_{oy} t+1/2(a_{y} )t^2

to solve for t

t=\sqrt{2(y-y_{0} )/a_{y} }

t=\sqrt{2(119m)/0.645m/s^2} =19.20s

6 0
3 years ago
A stone is thrown straight upward and reaches a maximum height of 31.8 m above its
atroni [7]

Answer:

aral ka muna ng mabuti para maintindihan mo

7 0
2 years ago
A charge of 5.67 x 10^-18 C is placed 3.5 x 10^-6 m away from another charge of -
Fudgin [204]
+ 1.58 e -15

Please hit thanks button! :)
5 0
1 year ago
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