Answer:
Explanation:
We have the reactions:
A: 
B: 
Our <u>target reaction</u> is:
We have 
as a reactive in the target reaction and is present in A reaction but in the products side. So we have to<u> flip reaction A</u>.
A: 
Then if we add reactions A and B we can obtain the target reaction, so:
A:
B: 
For the <u>final Kc value</u>, we have to keep in mind that when we have to <u>add chemical reactions</u> the total Kc value would be the <u>multiplication</u> of the Kc values in the previous reactions.
1.more
2.longer
3.warmer
4.northern
5.less
6.shorter
7.colder
8.southern
No of mole = reacting mass/ molar mass
No of mole = 0.06/56
No of mole = 0.00107mol....
Or...
1mole of iron contain 56gmol¯¹
:-x mole is contained in 0.06g
Porata
And you'll have..
x = 0.06/56
x = 0.00107mol.....
X is dependent Y is independent.... number of students is Y flavor is X
