7.2 × 10⁻³ J of energy is required to extend the pen

<h3>Further explanation</h3>
Let's recall Elastic Potential Energy formula as follows:

where:
<em>Ep = elastic potential energy ( J )</em>
<em>k = spring constant ( N/m )</em>
<em>x = spring extension ( compression ) ( m )</em>
Let us now tackle the problem!

<u>Given:</u>
length of spring = L = 1.8 cm
spring constant = k = 300 N/m
initial compression = x₁ = 1.0 mm = 1
final compression = x₂ = 1.0 + 6.0 = 7.0 mm
<u>Asked:</u>
energy required to extend the pen = ΔEp = ?
<u>Solution:</u>



![\Delta Ep = \frac{1}{2} \times 300 \times [ (7 \times 10^{-3})^2 - (1 \times 10^{-3})^2 ]](https://tex.z-dn.net/?f=%5CDelta%20Ep%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20300%20%5Ctimes%20%5B%20%287%20%5Ctimes%2010%5E%7B-3%7D%29%5E2%20-%20%281%20%5Ctimes%2010%5E%7B-3%7D%29%5E2%20%5D)


<h3>Conclusion :</h3>
7.2 × 10⁻³ J of energy is required to extend the pen

<h3>Learn more</h3>

<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Elasticity