Answer:
Explanation:
The amplitude of the oscillation under SHM will be .5 m and the equation of
SHM can be written as follows
x = .5 sin(ωt + π/2) , here the initial phase is π/2 because when t = 0 , x = A ( amplitude) , ω is angular frequency.
x = .5 cosωt
given , when t = .2 s , x = .35 m
.35 = .5 cos ωt
ωt = .79
ω = .79 / .20
= 3.95 rad /s
period of oscillation
T = 2π / ω
= 2 x 3.14 / 3.95
= 1.6 s
b )
ω = 
ω² = k / m
k = ω² x m
= 3.95² x .6
= 9.36 N/s
c )
v = ω
At t = .2 , x = .35
v = 3.95 
= 3.95 x .357
= 1.41 m/ s
d )
Acceleration at x
a = ω² x
= 3.95 x .35
= 1.3825 m s⁻²
Well first of all, when it comes to orbits of the planets around
the sun, there's no such thing as "orbital paths", in the sense
of definite ("quantized") distances that the planets can occupy
but not in between. That's the case with the electrons in an atom,
but a planet's orbit can be any old distance from the sun at all.
If Mercury, or any planet, were somehow moved to an orbit closer
to the sun, then ...
-- its speed in orbit would be greater,
-- the distance around its orbit would be shorter,
-- its orbital period ("year") would be shorter,
-- the temperature everywhere on its surface would be higher,
-- if it has an atmosphere now, then its atmosphere would become
less dense, and might soon disappear entirely,
-- the intensity of x-rays, charged particles, and other forms of
solar radiation arriving at its surface would be greater.
B: 210.8 rounded to 210 is totally wrong, and the reason why is because 210.8 rounded to the nearest whole number is 211, not 210. So B is the one with the error (this option is correct) and the other user that said D, is wrong since 18.42 does round to 18.4.
Hope this helped!
Nate
The distance a speaker should be placed behind other sound to have an amplitude 1.50 times is 4.523 m.
<h3>What is wavelength?</h3>
The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.
Wavelength λ = v/f
Two in-phase loudspeakers emit identical 1000 Hz sound waves along the x-axis.
λ = 343 m/s /1000 Hz
λ = 0.343 m
Distance, one should speaker be placed behind the other for the sound to have an amplitude 1.50 times that of each speaker alone.
The amplitude of the waveform due to waves,
A = 2a cos (ΔΦ/2)
ΔΦ = 2π x Δx/λ
So, A = 2a cos (π x Δx/λ)
Substitute the values, we get
1.5a = 2a cos (3.14 x Δx/ 0.343)
Δx = 4.523 m
Thus, the distance is 4.523 m.
Learn more about wavelength.
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