Calcium hypochlorite, Ca(OCl)2, is a bleaching agent produced from sodium hydroxide, calcium hydroxide, and chlorine. Socium chl
1 answer:
Answer: The missing coefficient is 2.
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
As in the products, there are 2 atoms of sodium, thus there will be 2 atoms of of sodium in the reactant as well. This will balance the number of hydrogen and oxygen atoms as well.
Thus the missing coefficient is 2.
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<u>Answer:</u> The mass of methane burned is 12.4 grams.
<u>Explanation:</u>
The chemical equation for the combustion of methane follows:
The equation for the enthalpy change of the above reaction is:
We are given:
Putting values in above equation, we get:
The heat calculated above is the heat released for 1 mole of methane.
The process involved in this problem are:
Now, we calculate the amount of heat released or absorbed in all the processes.
- <u>For process 1:</u>
where,
= amount of heat absorbed = ?
m = mass of water = 242.0 g
= specific heat of water = 4.18 J/g°C
= final temperature =
= initial temperature =
Putting all the values in above equation, we get:
- <u>For process 2:</u>
where,
= amount of heat absorbed = ?
m = mass of water or steam = 242 g
= latent heat of vaporization = 2257 J/g
Putting all the values in above equation, we get:
- <u>For process 3:</u>
where,
= amount of heat absorbed = ?
m = mass of steam = 242.0 g
= specific heat of steam = 2.08 J/g°C
= final temperature =
= initial temperature =
Putting all the values in above equation, we get:
Total heat required =
- To calculate the number of moles of methane, we apply unitary method:
When 802.34 kJ of heat is needed, the amount of methane combusted is 1 mole
So, when 621.552 kJ of heat is needed, the amount of methane combusted will be =
To calculate the number of moles, we use the equation:
Molar mass of methane = 16 g/mol
Moles of methane = 0.775 moles
Putting values in above equation, we get:
Hence, the mass of methane burned is 12.4 grams.