1. Option A. Temperature and Salinity
2. Option D. (I think)
3. Option D.
Hope your test goes well!
Molarity is expressed as the number of moles of solute per volume of the solution. For example, we are given a solution of 2M NaOH this describes a solution that has 2 moles of NaOH per 1 L volume of the solution. Acids and bases can be measured through the concentrations of H+ and OH- ions in units of molarity. Hope this helps.
Answer:
Are less reactive
Explanation:
Alkaline-earth metals are to the right of alkali metals.
The balanced chemical equation for the formation of methane from carbon and hydrogen is,
C + 2H2 --> CH4
This suggests that every 12 grams of C needs 4 grams of H in order to produce 16 grams of methane.
0.05 grams of hydrogen (H2) x (16 grams methane / 4 grams H) = 0.2 grams of methane.
1.20 grams carbon x (16 grams carbon / 12 grams of C) = 1.6 grams methane
We take the lower amount of carbon. Thus, the reaction will produce approximately 0.2 grams methane.
This is a PV=nRT problem. So to do this, you are looking for grams. The easiest way to get to grams is to convert moles, so set up the equation looking for n
n=PV/RT
To keep everything consistent with the universal gas constant (0.082057 L atm/mol K), one thing needs to be converted.
To convert 34.0 C to kelvin, just add 273.15. That gets 307.2 with sig figs.
Next, plug everything into your equation
n=(6.22atm)(16.6L)/(0.082057Latm/molK)(307.2K)
Cleaning that up gets you 4.10 moles (again, after sig figs)
Now, you need to convert the 4.10 moles of O2 to grams. To do that, you multiply 4.10 by 31.998 (molar mass of o2) to get 131 g (for a third time, sig figs!)
So, your final answer is 131 g O2
Sorry if any math is wrong, but you should be able to walk yourself through this and other problems now. Hope I helped!
