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lorasvet [3.4K]
3 years ago
11

Describe the factors that determine power in your own words (not from a website)

Physics
2 answers:
Olenka [21]3 years ago
7 0

Since you put your question in the <Physics> category, I'll assume
you're talking about mechanical or electrical power, and not political
or military power etc.

Power is the rate of doing work or moving energy from one place
to another.

In mechanical contraptions, Work is (force) x (distance) ,
so
                           Power = (work) divided by (time)

                               or     = (force) x (distance) divided by (time).

In electrical circuits,

                           Power = (voltage) x (current)

                               or    =  (current)² x (resistance)

                               or    =  (voltage)² divided by (resistance) .

(Just use the formula with whatever quantities you know.)

Bond [772]3 years ago
5 0

As it was categorized in the physics category it must be the mechanical power.


Power is basically the amount of work done per unit time or in simpler words the amount of energy transferred per unit time.


The SI unit for power is Watt. Which is basically J/s or Nm/s as wor has the unit of Nm.


In electrical components power can also be categorized as the amount voltage supplied multiplied by the current passed through the component.

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4 years ago
For Part A, Sebastian decided to use the copper cylinder. How would the magnitude of his q and ∆H compare if he were to redo Par
Vitek1552 [10]

The magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

The given parameters;

  • <em>initial temperature of metals, =  </em>T_m<em />
  • <em>initial temperature of water, = </em>T_i<em> </em>
  • <em>specific heat capacity of copper, </em>C_p<em> = 0.385 J/g.K</em>
  • <em>specific heat capacity of aluminum, </em>C_A = 0.9 J/g.K
  • <em>both metals have equal mass = m</em>

The quantity of heat transferred by each metal is calculated as follows;

Q = mcΔt

<em>For</em><em> copper metal</em><em>, the quantity of heat transferred is calculated as</em>;

Q_p = (m_wc_w + m_pc_p)(T_m - T_i)\\\\Q_p = (T_m - T_i)(m_wc_w ) + (T_m - T_i)(m_pc_p)\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m_p(T_m - T_i)\\\\m_p = m\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m(T_m - T_i)\\\\let \ (T_m - T_i)(m_wc_w )  = Q_i, \ \ \ and \ let \ (T_m- T_i) = \Delta t\\\\Q_p = Q_i + 0.385m\Delta t

<em>The </em><em>change</em><em> in </em><em>heat </em><em>energy for </em><em>copper metal</em>;

\Delta H = Q_p - Q_i\\\\\Delta H = (Q_i + 0.385m \Delta t) - Q_i\\\\\Delta H = 0.385 m \Delta t

<em>For </em><em>aluminum metal</em><em>, the quantity of heat transferred is calculated as</em>;

Q_A = (m_wc_w + m_Ac_A)(T_m - T_i)\\\\Q_A = (T_m -T_i)(m_wc_w) + (T_m -T_i) (m_Ac_A)\\\\let \ (T_m -T_i)(m_wc_w)  = Q_i, \ and \ let (T_m - T_i) = \Delta t\\\\Q_A = Q_i \ + \ m_Ac_A\Delta t\\\\m_A = m\\\\Q_A = Q_i \ + \ 0.9m\Delta t

<em>The </em><em>change</em><em> in </em><em>heat </em><em>energy for </em><em>aluminum metal </em><em>;</em>

\Delta H = Q_A - Q_i\\\\\Delta H = (Q_i + 0.9m\Delta t) - Q_i\\\\\Delta H = 0.9m\Delta t

Thus, we can conclude that the magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

Learn more here:brainly.com/question/15345295

6 0
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2. A wave on a rope has a wavelength of 2.0 m and a frequency of 2.0 Hz. What is the speed of the
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Answer:

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Explanation:

In order to calculate the speed of wave, you multiply the wavelength in meters and the frequency of the Wave in Hertz. 2 times 2 equals 4. The wave speed is always in m/s considering that the wavelength is also in meters.

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Chemical properties, on the other hand, are the things we can change with, for example, experiments and tools. Does it burn? Can it rust/oxidize? How does it react with other chemicals? Is it radioactive, or toxic? All of these are chemical properties you can probably answer.
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