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2 years ago

The highest energy waves have the {SHORTEST}wavelength

Physics

1 answer:

Likurg_2 [28]2 years ago

8 0

Answer:

infared rays pls give me brainiest]

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a 13-gram bullet, moving at 270 m/s, penetrates a 2 kg block of wood and emerges at a speed of 130 m/s. if teh block sits one a

saveliy_v [14]

Answer:

1.52m/s

Explanation:

Using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the final velocity

Substitute the given values into the formula

0.013(270)+2(130) = (270+130)v

3.51+260 = 400v

263.51 = 400v

v = 400/263.51

v = 1.52m/s

Hence the velocity after the bullet emerges is 1.52m/s

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3 years ago

Calculate the weight of your energy car if it has a mass of 233.85 kg.

lianna [129]

Explanation:

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2 years ago

All vehicles, including animal-drawn vehicles, must have at least one white light visible from a distance of not less than _____

Y_Kistochka [10]

1000 feet. Hope this helps.

5 0

2 years ago

If a car is traveling eastward, can its acceleration be westward?

KATRIN_1 [288]

Yes it can. It may be a bit counterintuitive but if the car is slowing down, even if it's traveling east, its acceleration is toward the west because it's decelerating and slowing down.

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3 years ago

Read 2 more answers

Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min, and its coarseness is such that it forms a pile in the shap

AURORKA [14]

Answer: The height of the pile increasing is increasing at $0.16\frac{ft}{min}$

Explanation:

Given

Rate at which gravel is being dumped , $\frac{\mathrm{d} V}{\mathrm{d} t}=10\frac{ft^{3}}{min}$

=>Rate of increase of volume of cone= $\frac{\mathrm{d} V}{\mathrm{d} t}=10\frac{ft^{3}}{min}$

If height of the cone at any instant is h then the diameter of cone is also h

Volume of cone , $V=\frac{\pi r^{2}h}{3}=\frac{\pi h^{3}}{4\times 3}=\frac{\pi h^{3}}{12}$

Now differentiate both sides w.r.t time(t)

$\frac{\mathrm{d} V}{\mathrm{d} t}=\frac{\pi h^{2}}{4}\frac{\mathrm{d} h}{\mathrm{d} t}$

Therefore at h = 9 ft

$10=\frac{\pi \times 9^{2}}{4}\times \frac{\mathrm{d} h}{\mathrm{d} t}$

=> $\frac{\mathrm{d} h}{\mathrm{d} t}=0.16\frac{ft}{min}$

Thus the height of the pile increasing is increasing at $0.16\frac{ft}{min}$

6 0

3 years ago