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faust18 [17]
3 years ago
14

A car is traveling around a horizontal circular track with radius r = 220 m at a constant speed v = 16 m/s as shown. The angle θ

A = 36° above the x axis, and the angle θB = 54° below the x axis. 1)
What is the x component of the car’s acceleration when it is at point A
Physics
1 answer:
iogann1982 [59]3 years ago
5 0
Velocity = distance / time = ( 2 * pi * r ) / t = 20.583 m/s 

<span>x component = sine ( 32 ° ) * 20.583 = 10.91 m/s

 hope this helps :)

</span>
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Which is usually greater for a pair of surfaces, the coefficient of static friction or the coefficient of sliding friction? why
lorasvet [3.4K]

Explanation :

Static friction is the frictional force between two objects that are at rest. While sliding friction is the frictional force between two objects in contact and are sliding w.r.t each other.

Static friction is usually greater than sliding friction because in static friction the contact forces is more and the interlocking between objects is tight as compared to sliding friction.    

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3 years ago
A train starting from rest picks up a speed of 20 m/s in 20 s while travelling on a straight path. It continues to move at the s
Andrej [43]

Answer:

1300 m

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The total distance covered by the train during the entire journey is the area of the speed-time graph.

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As velocity is in m/s and time is in s so the unit of area is m

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8 0
3 years ago
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Answer:

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Explanation:

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Answer:

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