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faust18 [17]
3 years ago
14

A car is traveling around a horizontal circular track with radius r = 220 m at a constant speed v = 16 m/s as shown. The angle θ

A = 36° above the x axis, and the angle θB = 54° below the x axis. 1)
What is the x component of the car’s acceleration when it is at point A
Physics
1 answer:
iogann1982 [59]3 years ago
5 0
Velocity = distance / time = ( 2 * pi * r ) / t = 20.583 m/s 

<span>x component = sine ( 32 ° ) * 20.583 = 10.91 m/s

 hope this helps :)

</span>
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