A car is traveling around a horizontal circular track with radius r = 220 m at a constant speed v = 16 m/s as shown. The angle θ

Question

2 years ago

14

A = 36° above the x axis, and the angle θB = 54° below the x axis. 1)
What is the x component of the car’s acceleration when it is at point A

1 answer:

iogann1982 [59] · Answer 1 · 2022-07-13T09:43:07+03:00

5 0

Velocity = distance / time = ( 2 * pi * r ) / t = 20.583 m/s

<span>x component = sine ( 32 ° ) * 20.583 = 10.91 m/s

hope this helps :)

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