A car is traveling around a horizontal circular track with radius r = 220 m at a constant speed v = 16 m/s as shown. The angle θ
A = 36° above the x axis, and the angle θB = 54° below the x axis. 1)
What is the x component of the car’s acceleration when it is at point A
1 answer:
Velocity = distance / time = ( 2 * pi * r ) / t = 20.583 m/s
<span>x component = sine ( 32 ° ) * 20.583 = 10.91 m/s
hope this helps :)
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hi <3
i believe i explained this answer properly in my last answer but it would be 4kg and 2400m as these are the SI units for these values.
hope this helps :)
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The parallel component is given by
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its c
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bc i know
It’s will be B because the circuit had a open or close so if that doesn’t work than it’s because it’s open
