Molar mass KCl = <span>74.5513 g/mol
Number of moles:
21.9 / 74.5513 => 0.293 moles
Volume = 869 mL / 1000 => 0.869 L
Molarity = moles / Volume
Molarity = 0.293 / 0.869
=> 0.337 M</span>
1 mol of Xe has a mass of 131 grams
x mol of Xe has a mass of 12 grams.
1/x = 131/12 Set up proportion from the information above. Cross multiply
131x = 12 Divide by 13`
x = 12/131
x = 0.0916 mol <<<< ====
Just for fun
I don't know if a calculator would even tell me the number of miles in 12 grams of Xe
The diameter is 216 * 10^-12 meters. Maybe.
1 mol of anything is 6.02 * 10^23
0.0912 mols contain x atoms
1/0.0912 = 6.02 * 10^23 / x
x = 0.0912 * 6.02 * 10^23
x = 5.49 * 10 ^ 22 This thing is going to stretch out quite a ways.
1 atom = 312 * 10^- 12 meters.
5.049 * 10^22 = x meters.
x = 312 * 10^-12 * 5.49 * 10^22
x = 1.7 * 10 ^10 km = 1.07 * 10 ^10 miles We're talking about beyond Pluto.
I'm sorry I should delete this. If you want to you can. Take my answer for the number of mols. It's likely correct.
Answer:
6.2g of NaBr are produced
Explanation:
The reaction of HBr with NaOH occurs as follows:
HBr + NaOH → NaBr + H2O
<em>Where 1 mole of each reactant produce 1 mole of NaBr</em>
To solve this question we need to find the moles of each reactant using their molar mass. With moles we can find limiting reactant and the moles (And mass) of NaBr produced, as follows:
<em>Moles HBr -Molar mass: 80.9119g/mol)-</em>
4.9g * (1mol/80.9119g) = 0.0606 moles HBr
<em>Moles NaOH -Molar mass: 40g/mol-</em>
3.86g * (1mol/40g) = 0.0965 moles NaOH
As the reaction is 1:1 and the moles of HBr < Moles NaOH, the limiting reactant is HBr and moles of NaBr produced are 0.0606 moles.
The mass of NaBr (Molar mass: 102.894g/mol) is:
0.0606 moles * (102.894g/mol) =
<h3>6.2g of NaBr are produced</h3>
Answer:Hence, the name of the NaOH is Sodium hydroxide.
Explanation:
In strong base NaOH is made up of three element sodium , oxygen and hydrogen.
NaOH dissociates is into cation and anion in its aqueous solution:
While naming the ternary compound:
- First write the name of cation present, here the cation is of sodium that
. - followed by space then write name of the anion , here anion present in a polyatomic anion that
, the name of this polyatomic anion is hydroxide.
Hence, the name of the NaOH is Sodium hydroxide.
