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Mkey [24]
3 years ago
9

Two electrons, each with mass mmm and charge qqq, are released from positions very far from each other. With respect to a certai

n reference frame, electron A has initial nonzero speed vvv toward electron B in the positive x direction, and electron B has initial speed 3v3v toward electron A in the negative x direction. The electrons move directly toward each other along the x axis (very hard to do with real electrons). As the electrons approach each other, they slow due to their electric repulsion. This repulsion eventually pushes them away from each other.
What is the minimum separation r_min that the electrons reach?

Physics
1 answer:
lana66690 [7]3 years ago
3 0

The answer & explanation for this question is given in the attachment below.

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Complete Question

The complete question is shown on the first uploaded image

Answer:

The value  is v  = 3.57 \  m/s

Explanation:

From the question we are told that

  The depth  is  d =  979 \  m

   The time taken for water to fall to below the river is  t =  14 \ s

   The  horizontal distance from the base of the vertical cliff is  h  =  50 \  m

     Generally  the horizontal speed at the top is mathematically represented as

         v  =  \frac{h}{t}

=>      v  =  \frac{  50}{ 14 }

=>     v  = 3.57 \  m/s

4 0
3 years ago
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