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3 years ago

What is the symbol of potassium chlorite

Chemistry

2 answers:

EleoNora [17]3 years ago

5 0

The symbol for potassium chloride is KCl. Potassium being (K), Chloride being (Cl).

tino4ka555 [31]3 years ago

4 0

Chlorite is ClO2^-1, and potassium is K with a charge of +1. So, we would write is as KClO2, since the charges cancel out with each other.

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A logarithmic scale is a nonlinear scale used when there is a large range of quantities

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3 years ago

A block of aluminum with a mass of 140 g is cooled from 98.4°C to 62.2°C with a release of 4817 J of heat. From these data, calc

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Answer:

specific heat = 0.951 j/g·°C

Explanation:

Heat flow equation => q = m·c·ΔT

q = heat flow = 4817 joules

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c = specific heat = ?

ΔT = Temperature Change in °C = 98.4°C - 62.2°C = 36.2°C

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2 years ago

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2 years ago

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2 years ago

A student heats a sample of hydrate once, and the mass of the sample and the evaporating dish is 16.428 g. After a second heatin

jolli1 [7]

Answer:

12.371 g

Explanation:

Given :

$m_{evaporating\ dish}=1.135\ g$

$m_{evaporating\ dish}+m_{Hydrate\ sample}=25.637\ g$

$m_{evaporating\ dish}+m_{First\ heated\ sample}=16.428\ g$

$m_{evaporating\ dish}+m_{Second\ heated\ sample}=13.266\ g$

Mass of salt hydrate:

$m_{evaporating\ dish}=1.135\ g$

$m_{evaporating\ dish}+m_{Hydrate\ sample}=25.637\ g$

$m_{Hydrate\ sample}=25.637-m_{evaporating\ dish}\ g=25.637-1.135\ g=24.502\ g$

Mass of salt anhydrous:

$m_{evaporating\ dish}=1.135\ g$

$m_{evaporating\ dish}+m_{Second\ heated\ sample}=13.266\ g$

$m_{Second\ heated\ sample}=m_{salt\ anhydrous}=13.266-m_{evaporating\ dish}\ g=13.266-1.135\ g=12.131\ g$

Mass of water:

$m_{water}=m_{Hydrate\ sample}-m_{salt\ anhydrous}=24.502-12.131\ g=12.371\ g$

$m_{water}=12.371\ g$

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3 years ago