For a body moving at a uniform velocity you can calculate the speed by dividing the distance traveled by the amount of time it took, for example one mile in 1/2 hour would give you 2 miles per hour. If the velocity is non-uniform all you can say is what the average speed is.
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Answer:
A 75.1 N and a direction of 152° to the vertical.
B 85.0 N at 0° to the vertical.
Explanation:
A) The interaction partner of this normal force has what magnitude and direction?
The interaction partner of this normal force is the component of the weight of the crate perpendicular to the ramp. <u>It has a magnitude of 85cos28° = 75.1 N and a direction of 180° - 28° = 152° to the vertical(since it is directed downwards perpendicular to the ramp).</u>
B) The normal and frictional forces are perpendicular components of the contact force exerted on the crate by the ramp. What is the magnitude and direction of the contact force?
Since this force has to balance the weight of the crate, its magnitude is 85.0 N. Its direction has to be vertically opposite to that of the weight.
Since the weight is 180° to the vertical (since it is directed downwards), this force is 0° to the vertical.
<u>So, this force has a magnitude of 85.0 N and a direction of 0° to the vertical.</u>
The maximum velocity reached by the person is determined as 11.1 m/s.
<h3>Area under velocity - time graph</h3>
The area under the velocity time graph is the total displacement of the person.
Total Area = area of triangle formed during first 2 seconds + area of rectangle during the last 8 seconds
100 = ¹/₂(2v) + v(11 - 2)
where;
- v is the maximum velocity
100 = v + 8v
100 = 9v
v = 100/9
v = 11. 1 m/s
Thus, the maximum velocity reached by the person is determined as 11.1 m/s.
Learn more about maximum velocity here: brainly.com/question/20595261
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Answer:

Explanation:
First displacement of the particle is given as
= 11 m at 82 degree with positive X axis
so we can say


resultant displacement of the particle after second displacement is given as
r = 8.7 m at 135 degree with positive X axis
so we can say


now we know that

now we have

so we will have


so angle of the second displacement is given as


