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coldgirl [10]
3 years ago
15

For which of the following activities might you want to hire a chemist?

Chemistry
1 answer:
yarga [219]3 years ago
5 0

examining the structure of plant cells

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PLEASE HELP ME Which of the following is a Brønsted-Lowry base but not an Arrhenius base?
never [62]
Ur answer is going to be <span>NH 3 or D AND PLEASE MARK ME AS BRAINLIEST CAUSE IVE NEVER GOT BRAINLIEST BEFORE AND HAVE A GOOD DAY !</span>
4 0
3 years ago
A(n) ________ is a group of atoms that determines many of the properties of an organic molecule.
Leno4ka [110]
A functional group is a group of atoms that determines many of the properties of an organic molecule.
For example functional group for alcohol is hydroxyl group (-OH) and for carboxylic acid is <span>carboxyl group (-COOH).
</span>Alpha carbon is <span>the first </span>carbon<span> atom after the carbon that attaches to the functional group.</span>
4 0
3 years ago
Nitrogen ion (Nitride) is ... Cation/Anion/Neither? # of protons? # of electrons? Charge (1-, 2-, 3-, 1+, 2+, 3+, or 0) Number o
OLga [1]

Answer:

3- is the charge and 8 dots on its Lewis dot structure.

Explanation:

Hello there!

In this case, since nitrogen is an element with five valence electrons (electrons on its outer shell), we infer that it needs three bonds to complete the octet, for which its charge, when forming nitride ions is 3-, which means it has received three electrons. Thus, when drawing the Lewis dot structure, it is evident that is will have 5+3 = 8 dots due to the electron reception.

Regards!

8 0
2 years ago
An atom of element A has 108 protons. What would the elements atomic number be?
marusya05 [52]

108 is the atomic number

3 0
3 years ago
The enthalpy of combustion of hard coal averages -35 kJ/g, that of gasoline, 1.28 x 105 kJ/gal. How many kilograms of hard coal
Ganezh [65]

Answer:

3.657 kg

Explanation:

Given:

Enthalpy of combustion of hard coal = -35 kJ/g

Enthalpy of combustion of gasoline = 1.28 × 10⁵ kJ/gal

Density of gasoline = 0.692 g/mL

now,

The heat provide 1 gallon of gasoline provide =  1.28 × 10⁵ kJ

and,

heat provided by the 1 gram of coal  = 35 kJ

or

1 kJ of heat is provided by (1/35) gram of hard coal

therefore,

For 1.28 × 10⁵ kJ of heat, mass of hard coal =  1.28 × 10⁵ kJ × (1 / 35)

or

For 1.28 × 10⁵ kJ of heat, mass of hard coal = 3657.14 grams = 3.657 kg

3 0
3 years ago
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