Answer:
O2 is limiting reactant
Explanation:
To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:
<em>Moles C6H12O6:</em>
650g * (1mol/180.16g) = 3.608 moles C6H12O6
<em>Moles O2:</em>
650g * (1mol/32g) = 20.31 moles O2
Now, for a complete reaction of 3.608 moles of C6H12O6 are required:
3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2
As there are just 20.31 moles of O2,
<h3>O2 is limiting reactant</h3>
Answer:
I would say the purple one!
Explanation:
Answer:
Pollination is the act of transferring pollen grains from the male anther of a flower to the female stigma. The goal of every living organism, including plants, is to create offspring for the next generation. One of the ways that plants can produce offspring is by making seeds.
Explanation:
hoped it helped
Answer:
<em>17500 calories</em> of chocolate bars are needed to eat to gain 5 pounds.
Explanation:
We can use ratios to calculate the answer using the information given in the question.
1 pound : 3500 grams
5 pounds : x grams
As it is given that the individual is burning no calories, we do not have to factor in any additional numbers.
<u><em>Method</em><em> </em><em>A</em><em>:</em></u>
To go from 1 in the first ratio to 5 in the second ratio, they multipled 1 by 5. Hence, to go from 3500 in the first ratio to x in the second ratio, we must multiply by 5.
x = 3500 × 5
x = 17500
<em><u>Method B</u>:</em>
To solve for the answer x, we can convert the ratios into fractions.
1 / 5 = 3500 / x
3500 / x = 1 / 5
To make x the subject, multiply the denominator of the left fraction with the numerator of the right fraction and place it on the left side. Then multiply the numerator of the left fraction with the denominator of the right fraction and place it on the right side.
x = 5 × 3500
x = 17500
The amount of liquid is measured in L. As the unit Lm is only used when measuring the mass liquid fraction.
