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Bond [772]
2 years ago
5

Sodium bicarbonate =sodium carbonate + water + carbon dioxide gas

Chemistry
1 answer:
SashulF [63]2 years ago
4 0

Answer: NaHCO3 = Na2CO3 + H2O + CO2

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Question 5
pantera1 [17]

Answer: The coefficient for the diatomic oxygen (O2) is 3.

Explanation:

To know the coefficient for the diatomic Oxygen, we need to balance the equation.

Fe + O2 ------->   Fe2O3

LHS of the equation; Fe =  1    , O2 = 1

RHS of the equation; Fe = 2 ,  O = 3

∴ Multiply 'Fe' on the LHS of the equation by 4 and O2 by 3

   Doing that will give the balance equation which is;

   4 Fe +  3 O2  --------> 2 Fe2O3

The coefficient for the diatomic oxygen (O2) as seen from the equation is 3.

7 0
2 years ago
How would life be different without polythene
Alexxx [7]
Without plastic, we wouldn't have as much of an environmental problem as we have now. Even though plastic has a lot of negatives, it's also made our lives a lot easier over past years. ... Our cars would have been different since a lot of the materials used inside are made out of plastic.
7 0
2 years ago
Which of the substances are elements please help
ivanzaharov [21]

Answer:

Substances 1 and 2

Explanation:

an element only has 1 kind of atoms :3

6 0
3 years ago
Select all that are true
kipiarov [429]
I think it’s B not quite sure ! Sorry
8 0
2 years ago
A strontium hydroxide solution is prepared by dissolving 10.60 gg of Sr(OH)2Sr(OH)2 in water to make 47.00 mLmL of solution.What
NeTakaya

Answer:

Approximately 1.854\; \rm mol\cdot L^{-1}.

Explanation:

Note that both figures in the question come with four significant figures. Therefore, the answer should also be rounded to four significant figures. Intermediate results should have more significant figures than that.

<h3>Formula mass of strontium hydroxide</h3>

Look up the relative atomic mass of \rm Sr, \rm O, and \rm H on a modern periodic table. Keep at least four significant figures in each of these atomic mass data.

  • \rm Sr: 87.62.
  • \rm O: 15.999.
  • \rm H: 1.008.

Calculate the formula mass of \rm Sr(OH)_2:

M\left(\rm Sr(OH)_2\right) = 87.62 + 2\times (15.999 + 1.008) = 121.634\; \rm g \cdot mol^{-1}.

<h3>Number of moles of strontium hydroxide in the solution</h3>

M\left(\rm Sr(OH)_2\right) =121.634\; \rm g \cdot mol^{-1} means that each mole of \rm Sr(OH)_2 formula units have a mass of 121.634\; \rm g.

The question states that there are 10.60\; \rm g of \rm Sr(OH)_2 in this solution.

How many moles of \rm Sr(OH)_2 formula units would that be?

\begin{aligned}n\left(\rm Sr(OH)_2\right) &= \frac{m\left(\rm Sr(OH)_2\right)}{M\left(\rm Sr(OH)_2\right)}\\ &= \frac{10.60\; \rm g}{121.634\; \rm g \cdot mol^{-1}} \approx 8.71467\times 10^{-2}\; \rm mol\end{aligned}.

<h3>Molarity of this strontium hydroxide solution</h3>

There are 8.71467\times 10^{-2}\; \rm mol of \rm Sr(OH)_2 formula units in this 47\; \rm mL solution. Convert the unit of volume to liter:

V = 47\; \rm mL = 0.047\; \rm L.

The molarity of a solution measures its molar concentration. For this solution:

\begin{aligned}c\left(\rm Sr(OH)_2\right) &= \frac{n\left(\rm Sr(OH)_2\right)}{V}\\ &= \frac{8.71467\times 10^{-2}\; \rm mol}{0.047\; \rm L} \approx 1.854\; \rm mol \cdot L^{-1}\end{aligned}.

(Rounded to four significant figures.)

5 0
2 years ago
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