E is Bohrs model the dots on the rings represent the valence electrons
Rutile (TiO2) or ilmenite (FeTiO3) titanium-containing minerals has the larger percentage of titanium is explained below.
Explanation:
1. Titanium is obtained from different ores that occur naturally on the Earth. Ilmenite (FeTiO3) and rutile (TiO2) are the most important sources of titanium.
2. According to USGS, Ilmenite(FeTio3) accounts for about 92% of the world’s consumption of titanium minerals.
3. World resources of anatase, ilmenite and rutile total more than 2 billion tonnes. Identified reserves total 750 million tonnes (ilmenite plus rutile).
4. China, with 20 million tonnes--accounting for 29% of the world total-- is now the country that is most abundant in terms of ilmenite reserves. Meanwhile, Australia, with 24 million tones rutile reserves—accounting for 50% of the world total—is now the country that is most abundant in terms of rutile reserves.
5.Ilmenite can be mined from both layered intrusive deposits and heavy mineral deposits. It is often found alongside rutile in heavy mineral deposits. Ilmenite is used to make titanium dioxide pigment or it can be processed into feedstock that can be used in the manufacture of titanium. This has become more common as viable rutile deposits become increasingly scarce. South Africa and Australia are among the world’s largest producer of Ilmenite, each extracting over a million metric tonnes per year.
6.The Mining of titanium from intrusive rock is restricted to ilmenite and its weathered derivative leucoxene. The largest opencast ilmenite mine is Tellnes in Norway’s municipality of Sokndal.
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In this problem, we need to use the ideal gas law. The following is the formula used in ideal gas law: PV = nRT, where n refers to the moles and R is the gas constant.
Given
P = 10130.0 kPa
V = 50 L
T = 300 degree celcius + 273.15 = 573.15 K
R = 8.314 L. kPa/K.mol
Solution
To get the moles which represent the "n" in the formula, we need to rearrange the equation.
PV = nRT PV
---- ------ ---> n = --------
RT RT RT
10130.0 kPa x 50 L
n= ---------------------------------------------
8.314 L. kPa/K.mol x 573.15 K
506,500
= ----------------------------
4,765.17 mol K
=106.29 mol Ar
So the moles of argon gas is 106.29 moles
