Answer:
When a solid turns to a gas.
Explanation:
Answer:
e. 327/227
Explanation:
This is the correct standard pressure.
Answer:
33.8 m
Explanation:
(a) We want to know the molality of nitric acid in a concentrated solution of nitric acid (68.0% HNO₃ by mass).
Step 1: Determine the mass of HNO₃ and water in 100 grams of solution.
Step 2: Convert the mass of HNO₃ to moles.
Step 3: Convert the mass of water to kilograms.
Step 4: Calculate the molality.
(b)
Step 1
In 100 g of solution, there are 68.0 g of HNO₃ and 100 g - 68.0 g = 32.0 g of water.
Step 2
The molar mass of HNO₃ is 63.01 g/mol. The moles corresponding to 68.0 g are:
68.0 g × (1 mol/63.01 g) = 1.08 mol
Step 3
The mass of water is 32.0 g = 0.0320 kg
Step 4
The molality of HNO₃ is:
m = moles of solute / kilograms of solvent
m = 1.08 mol / 0.0320 kg
m = 33.8 m
A scientific law<span> is a statement based on repeated experimental observations that describes some aspects of the universe. A </span>scientific law<span> always applies under the same conditions, and implies that there is a causal relationship involving its elements.</span>
Answer:
Molar mass of the unknown gas: 146 g /mol
Explanation:
At STP, any "ideal" gas is contained in a volume of 22.4L. This situation, for 1 mol of gas. In this case we have:
0.5 g / 4 g/mol = 0.125 moles of He
These amount of He occupies 0.125 mol . 22.4L / 1 mol = 2.8 L so the double of volume will be occupied by the unkown gas.
22.4 L / 1 mol = (2.8 L . 2) / x moles
22.4L / 1 mol = 5.6 L / x mol
x mol = 5.6L / 22.4L → 0.25 moles
To determine the molar mass of the unknown gas → 36.5 g / 0.25 mol = 146 g /mol
