Which of the following occurs as temperature increases?

What kingdom is Spirogyra in?

jasenka [17]

Protista .................................

8 0

3 years ago

Which of the following includes a wedge.<br>A.axe<br> B.file<br>c.bolt<br>d.hammer

faust18 [17]

The correct answers would be A, and D

3 0

3 years ago

Read 2 more answers

Write the formula for potassium oxide. why do you not need prefixes in the name

Molodets [167]

Potassium oxide: K₂O.

There's no need for prefixes since K₂O is an ionic compound.

<h3>Explanation</h3>

Find the two elements on a periodic table:

Potassium- K- on the left end of period four.
Oxygen- O- near the right end of periodic two.

Elements on the bottom-left corner of the periodic table are metals. Those on the top-right corner are nonmetals.

Potassium is a metal,
Oxygen is a nonmetal.

A metal and a nonmetal combine to form an ionic compound. Potassium oxide is likely to be an ionic compound. It contains two types of ions:

Potassium ions: Potassium is group 1 of the periodic table. It is an alkaline metal. Like other alkaline metals such as sodium Na, potassium K tends to lose one electron and form ions of charge +1 in compounds. The ion would be K⁺.

Oxide ions from oxygen: Oxygen is the second most electronegative element on the periodic table. It tends to gain two electrons and form the oxide ion $\text{O}^{2-}$ when it combines with metals.

The two types of ions carry opposite charges. They shall pair up at a certain ratio such that they balance the charge on each other. The charge on each $\text{O}^{2-}$ ion is twice that on a $\text{K}^{+}$ ion. Each $\text{K}^{+}$ would pair up with two $\text{O}^{2-}$ . Hence the subscript in the formula: $\text{K}_{\bf 2}\text{O}$ .

There are two classes of compounds:

Covalent compounds, which need prefixes, and
Ionic compounds, which need no prefix.

Prefixes are needed only in covalent compounds. For instance in the covalent compound carbon dioxide $\text{CO}_2$ , the prefix di- indicates that there are two oxygen atoms in the formula $\text{CO}_2$ . However, there's no need for prefix in ionic compounds such as $\text{K}_2\text{O}$ .

7 0

3 years ago

A gaseous mixture of 10.0 volumes of CO₂, 1.00 volume of unreacted O₂, and 50.0 volumes of unreacted N₂ leaves an engineat 4.0 a

ycow [4]

The masses of CO and CO2 are 90.55g and 100−90.55=9.45 g respectively.

<h3>Total mass.</h3>

Let the mixture has 100g as total mass.

The number of moles of CO is 2890.55=3.234.

The number of moles of CO2 is 449.45=0.215.

The mole fraction of CO is 3.234+0.2153.234=0.938.

The mole fraction of CO2 is 1−0.938=0.062.

The partial pressure of CO is the product of the mole fraction of CO and the total pressure.

It is 0.938×1=0.938 atm.

The partial pressure of carbon dioxide is 0.062×1=0.042 atm.

The expression for the equilibrium constant is:

Kp=PCO2PCO2=0.062(0.938)2=14.19

Δng=2−1=1

Kc=Kp(RT)−Δn=14.19×(0.0821×1127)−1=0.153.

To learn more about equilibrium constant visit the link

brainly.com/question/15118952

#SPJ4

3 0

1 year ago

The products obtained from hydroboration-oxidation of cis-2-butene are identical to the products obtained from hydroboration-oxi

Rudik [331]

Answer:

a) Attached below

b) The presence of racemic mixture found as product in both cases shows that products are identical ( i.e. they have same configuration

Explanation:

Diagrams of the products obtained from hydroboration-oxidation of cis-2-butene , hydroboration-oxidation of trans-2-butene.

attached below

The presence of racemic mixture found as product in both cases shows that products are identical ( i.e. they have same configuration )

7 0

3 years ago