The launch velocity of the marble launcher is 34.65 m/s
Given that the launch velocity of marble launcher, launches a 25g marble to a distance of 73 cm (0.73 m) and the marble roll up to 6.2 meters before stopping. The launch height is 20 cm (0.2 m).
The time for landing can be calculated by the second equation of motion formula:
h = ut + 
g
Let u = 0
0.2 = 0×t + × 9.8 ×
= 
= 0.04
t = 0.2s
Now, the launch velocity of the marble launcher can be calculated by:
Speed = Distance / Time
Speed = 
Speed = 
Speed = 34.65 m/s
Therefore, the launch velocity of the marble launcher is 34.65 m/s
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Answer:
d) The stone will have about 50 joules of kinetic energy and 0 joules of potential energy .
Explanation:
Given :
Initial Potential energy , 
.
Initial Kinetic energy , 
. ( because ball is in rest )
Now , we know , kinetic energy is maximum when an object reaches ground .
Also , potential energy is zero when an object is in ground .
We know , by conservation of energy :
Initial total energy = Final total energy
Therefore , option d) is correct .
Answer:
970.2 N
Explanation:
We are given that
Length of ladder=2.7 m
Mass,M=11 kg
Coefficient of friction=
Mass of painter=8M
Distance from base=d
We have to find the magnitude of the normal force exerted by the floor on the ladder.
Normal force exerted by floor on the ladder=
Where 
Normal force exerted by floor on the ladder=
Answer:
This means that the center of mass is locates 0.72m from the 750N force
Explanation:
Since the board is 2.2m long, that will be the length of the board.
Let the center of mass of the body be hinged at the center using a knife edge as shown in the diagram attached.
Let x be the distance from the 750N force to the knife edge and the distance from the 360N force to the knife edge be 2.2-x
Using the principle of moment which states that the sum of clockwise moment is equal to the sum of anti clockwise moment.
Moment = force × perpendicular distance
For ACW moment;
Moment = 750×x = 750x
For the CW moment;
Moment = 360 × (2.2-x)
Moment = 792-360x
Equating ACW moment to the clockwise moment we have;
750x = 792-360x
750x+360x = 792
1110x = 792
x = 792/1110
x = 0.72m
This means that the center of mass is locates 0.72m from the 750N force
The diagram is in the picture attached.
Options are:
A) 32 °C
B) 70 °C
C) 92 °C
D) 100 °C
In order to find the value required, you need to look at the diagram and follow these steps:
1) search for the value of 70 kPa on the y-axis;
2) move on a horizontal line towards the right until you reach the line D;
3) move on a vertical line down, towards the x-axis;
4) read at what value of °C you are at.
Doing so, you can see that you are at a value a little bit above 90 °C (see picture).
Hence, the correct answer is
C) 92°C.
