Answer:
Explanation:
1 ) Let the initial horizontal velocity of car be v .
For vertical displacement
vertical displacement h = 21.3 - 2.3 = 19 m
Time taken to fall by 19 m be t
19 = 1/2 x 9.8 t² ( initial downward velocity is zero )
t = 1.97 s
This is also the time taken to cover horizontal displacement of 54 m which is width of river .
horizontal speed v = 54 / 1.97 m /s
v = 27.41 m /s
2 )
At the time of landing on other side , car will have both vertical and horizontal speed .
vertical speed
v = u + gt
= 0 + 9.8 x 1.97 = 19.31 m /s
horizontal speed will remain same as the initial speed = 27.41 m /s
Resultant speed = √ ( 27.41² + 19.31² )
= √ ( 751.3 + 372.87)
= 33.52 m /s
The distances to the most of these galaxies estimated from their red shifts and the application of Hubble's Law.
<h3>What is Hubble's Law?</h3>
The discovery in physical cosmology that galaxies are travelling away from Earth at rates proportionate to their distance is known as Hubble's law, often referred to as the Hubble-Lemaître law or Lemaître's law. In other words, they are travelling away from Earth more quickly the more away they are. The redshift of the galaxies—a shift in the light they produce toward the red end of the visible spectrum—has been used to calculate their velocities.
The Sloan Digital Sky Survey includes many thousands of galaxies in its spectroscopic catalogs. The distances to the most of these galaxies estimated
from their red shifts and the application of Hubble's Lawh
to learn more about Hubble's law go to - brainly.com/question/3050512
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Answer:
this happens because there is gravitational force acting upon it.
Answer:
a) T = 2.26 N, b) v = 1.68 m / s
Explanation:
We use Newton's second law
Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string
sin 30 = 
cos 30 = 
Tₓ = T sin 30
T_y = T cos 30
Y axis
T_y -W = 0
T cos 30 = mg (1)
X axis
Tₓ = m a
they relate it is centripetal
a = v² / r
we substitute
T sin 30 = m
(2)
a) we substitute in 1
T = 
T = 
T = 2.26 N
b) from equation 2
v² = 
If we know the length of the string
sin 30 = r / L
r = L sin 30
we substitute
v² = 
v² = 
For the problem let us take L = 1 m
let's calculate
v = 
v = 1.68 m / s
