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d1i1m1o1n [39]
3 years ago
8

Which MOST CLOSELY identifies a theme in this passage?

Chemistry
1 answer:
Delicious77 [7]3 years ago
8 0

Answer:

B)

Explanation:

It is the theme of the passage.

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Calculate the quotient [co32–]/[hco3–] at ph 10.75.
KATRIN_1 [288]

The chemical equation is:

<span>HCO3^    ->  H^+ + CO3^2- </span>

 

We know that the formula for Ka is:
Ka = [H^+][CO3^2-]/[HCO3^-] 


log Ka = log[H^+] + log[CO3^2-]/[HCO3^-] 
pKa = pH - log[CO3^2-]/[HCO3^-] 
log[CO3^2-]/[HCO3^-] = pH - pKa = 10.75 - 10.329 = 0.421 
<span>[CO3^2-]/[HCO3^-] = Antilog (0.421)  = 2.636 </span>

 

Answer:

<span>2.636</span>

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A 13.00 g sample of a compound contains 4.15 g potassium (k), 3.76 g chlorine (cl), and oxygen (o). calculate the empirical form
MrRissso [65]

To solve this problem, let us all convert the mass of each element into number of moles using the formula:

moles = mass / molar mass

Where,

molar mass K = 39.10 g / mol

<span>molar mass Cl = 35.45 g / mol</span>

molar mass O = 16 g / mol

<span>and mass O = 13 g – 4.15 g – 3.76 g  = 5.09 g</span>

 

moles K = 4.15 g / (39.10 g / mol) = 0.106 mol

<span>moles Cl = 3.76 g / (35.45 g / mol) = 0.106 mol</span>

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The ratio becomes:

0.106 K: 0.106 Cl: 0.318 O

We divide all numbers with the smallest number, in this case 0.106. This becomes:

K: Cl: 3O

 

Therefore the empirical formula is:

KClO_{3}

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If the pressure on an ideal gas is increased, what will happen to the volume of the gas?
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