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d1i1m1o1n [39]
3 years ago
8

Which MOST CLOSELY identifies a theme in this passage?

Chemistry
1 answer:
Delicious77 [7]3 years ago
8 0

Answer:

B)

Explanation:

It is the theme of the passage.

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Classify each of the following properties as physical or chemical: A. Ice melts in the sun. B. Copper is a shiny metal. C. Paper
vampirchik [111]

Answer:

The answer to your question is below

Explanation:

Physical properties are the properties in which there is no change in the nature of the substance  but there is a change in the physical state.

Chemical properties are the properties in which the substance changes its nature. A new substance is formed.

A. Ice melts in the sun. Physical p.

B. Copper is a shiny metal. Physical p.

C. Paper can burn. Chemical p.

D. A silver knife can tarnish. Physical p.

E. A magnet removes iron particles from a mixture. Physical p.

8 0
3 years ago
Why can’t an atom lose or gain a proton
Veronika [31]

Explanation:

Atoms never gain protons; they become positively charge only by losing electrons. A positive ion is called a cation (pronounced: CAT-eye-on). You may have notice that the number of neutrons in each of these ions was not specified.

6 0
3 years ago
Read 2 more answers
Solids we need to live
gogolik [260]
Foods are a solid we need to survive
6 0
4 years ago
A reaction that breaks large molecules into smaller ones by the addition of water is called a(n):
Luda [366]
Answer:  "condensation reaction" .
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5 0
3 years ago
How much carbon would be needed to make 8.8g of carbon dioxide?<br>​
PIT_PIT [208]
The calculation for such a question can be achieved via Avogadro hypothesis

We know molar mass of CO2 is 44g/mole which is the sum of atomic masses i.e; C and 2 oxygen atoms

Molar mass of CO2 =12(C)+2*16(O) = 44 g/mole will contain 6.023 ※10^23 CO2 molecules ..

44g/mole = 6.023 ※10^23 CO2 molecules

=> 1g = (6.023/44) ※10^23 CO2 molecules

==> 8.80g = 8.80(6.023÷44)10^23 = 1.2046 ※10^23 molecules of CO2….

Thus there r 1.2046 ※10^23 molecules of CO2 in 8.80g

if u need to calculate no. of carbon atoms then multiply result by 1 and if u need no of oxygen atoms in 8.80g of co2 then multiply the result by 2 ….
7 0
2 years ago
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