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3 years ago

Part A

Chemistry

2 answers:

ArbitrLikvidat [17]3 years ago

6 0

Answer:

I don't think it will

Explanation:

because Javier is moving which is causing for the temperature to change.

Kipish [7]3 years ago

6 0

Answer:

No, they will not have the same temperature.

Explanation:

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The highly reactive elements in group 7A are known for forming salts. What are they called? transition metals metalloids halogen

liberstina [14]

The group 7A elements are called Halogens.

Please mark as brainliest if this helped! :)

4 0

3 years ago

Write the balanced reaction using the fewest whole number coefficients to describe the reaction between gaseous hydrogen and gas

Anastasy [175]

<u>Answer:</u> The percentage yield of water is 9.5 %

<u>Explanation:</u>

We are given:

Moles of hydrogen = 14 moles

Moles of oxygen = 10 moles

The chemical equation for the formation of water from hydrogen and oxygen follows:

$2H_2+O_2\rightarrow 2H_2O$

By Stoichiometry of the reaction:

2 moles of hydrogen gas reacts with 1 mole of oxygen gas

So, 14 moles of hydrogen gas will react with = $\frac{1}{2}\times 14=7mol$ of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of hydrogen gas produces 2 moles of water

So, 14 moles of hydrogen gas will produce = $\frac{1}{2}\times 14=7mol$ of water

To calculate the percentage yield of water, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of water = 1.33 moles

Theoretical yield of water = 14 moles

Putting values in above equation, we get:

$\%\text{ yield of water}=\frac{1.33mol}{14mol}\times 100\\\\\% \text{yield of water}=9.5\%$

Hence, the percent yield of the water is 9.5 %.

7 0

3 years ago

Calculate ΔrG∘ at 298 K for the following reactions.CO(g)+H2O(g)→H2(g)+CO2(g)2-Predict the effect on ΔrG∘ of lowering the temper

KonstantinChe [14]

Answer:

1) ΔG°r(298 K) = - 28.619 KJ/mol

2) ΔG°r will decrease with decreasing temperature

Explanation:

CO(g) + H2O(g) → H2(g) + CO2(g)

1) ΔG°r = ∑νiΔG°f,i

⇒ ΔG°r(298 K) = ΔG°CO2(g) + ΔG°H2(g) - ΔG°H2O(g) - ΔG°CO(g)

from literature, T = 298 K:

∴ ΔG°CO2(g) = - 394.359 KJ/mol

∴ ΔG°CO(g) = - 137.152 KJ/mol

∴ ΔG°H2(g) = 0 KJ/mol........pure substance

∴ ΔG°H2O(g) = - 228.588 KJ/mol

⇒ ΔG°r(298 K) = - 394.359 KJ/mol + 0 KJ/mol - ( - 228.588 KJ/mol ) - ( - 137.152 KJ7mol )

⇒ ΔG°r(298 K) = - 28.619 KJ/mol

2) K = e∧(-ΔG°/RT)

∴ R = 8.314 E-3 KJ/K.mol

∴ T = 298 K

⇒ K = e∧(-28.619/(8.314 E-3)(298) = 9.624 E-6

⇒ ΔG°r = - RTLnK

If T (↓) ⇒ ΔG°r (↓)

assuming T = 200 K

⇒ ΔG°r(200 K) = - (8.314 E-3)(200)Ln(9.624E-3)

⇒ ΔG°r (200K) = - 19.207 KJ/mol < ΔG°r(298 K) = - 28.619 KJ/mol

6 0

3 years ago

A volatile liquid is one that ______?

nasty-shy [4]

readily evaparates.

hope it helped :D

7 0

3 years ago

What do lysosomes and Golgi bodies have in common?

Drupady [299]

The first question would be B) they are examples of cell organelles. The second question would be A) mitochondria. Hope this helps!

5 0

3 years ago

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